(1) You must find the point of equilibrium between the two forces,
<span>G * <span><span><span>MT</span><span>ms / </span></span><span>(R−x)^2 </span></span>= G * <span><span><span>ML</span><span>ms / </span></span><span>x^2 MT / (R-x)^2 = ML / x^2
So,
x = R * sqrt(ML * MT) - ML / (MT - ML) R = is the distance between Earth and Moon.
</span></span></span>The result should be,
x = 3.83 * 10^7m from the center of the Moon, and
R - x = 3.46*10^8 m from the center of the Earth.
(2) As the distance from the center of the Earth is the number we found before, d = R - x = 3.46*10^8m The acceleration at this point is g = G * MT / d^2 g = 3.33*10^-3 m/s^2