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WITCHER [35]
3 years ago
6

Which substance has a lower coefficient of friction?

Physics
2 answers:
Zarrin [17]3 years ago
8 0
Should be slip n slide with oil since it’s more likely to create more friction than just a normal slip n slide.
Talja [164]3 years ago
3 0
Slip and slide covered with oil
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What is the volume of the cylinder with a height of 13cm and a radius of 4cm
nordsb [41]
The volume is 653.45 cm³
6 0
4 years ago
- A capacitor's dielectric material is a vacuum. The capacitor's dielectric constant, or K, will be equal to
dlinn [17]

If  a capacitor's dielectric constant is vacuum its dielectric constant is k will be equal to 1.

<u>Explanation:</u>

Relative permittivity of  a dielectric substance is referred to as its dielectric constant. Relative permittivity/dielectric constant k is a dimensionless quantity that is the ratio of absolute permittivity and vacuum permittivity.

It is given by the expression

k=k=ε /ε0

where ε denotes absolute permittivity and  ε0 denotes permittivity of vacuuum.

Absolute permittivity  ε of vacuum= ε0

therefore k= ε0/ ε0=1

dielectric constant of vacuum is 1 .

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3 years ago
What happens when the moon travels between the earth and the sun, causing the sun to become obscured from view?
nadya68 [22]
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4 years ago
A car has a mass of 850 kg. By pushing on the car, Evan increases its speed
Dmitry_Shevchenko [17]

Answer:

I=1,2•10³ kg•m/s

Explanation:

v¹=3.5m/s

vf=5m/s

v=5-3.5=1.5m/s

I=p

I=mv=850•1.5=1275 kg•m/s=1,2•10³ kg•m/s

8 0
4 years ago
Read 2 more answers
How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?
Aleonysh [2.5K]

<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Given that ,

  • Initial Velocity of car = 44km / hr.
  • Final Velocity of car = 0km / hr.
  • Acceleration = -5km/hr².

To Find :

  • Time taken to stop the car .

So , here use first equⁿ of motion which is ,

\boxed{\red{\bf\dag v = u + at }}

where ,

  • v is final Velocity.
  • u is Initial velocity.
  • a is acceleration.
  • t is time taken.

Now , substituting the respective values ,

\tt:\implies v=u+at

\tt:\implies 0 = 44 + (-5)t

\tt:\implies -44 = -5t

\tt:\implies t=\dfrac{44}{5}

\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}

\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}

6 0
3 years ago
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