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densk [106]
2 years ago
14

What is the pun when I go from here to there quickly on foot

Chemistry
1 answer:
zlopas [31]2 years ago
6 0
1. A type of mens cologne
2. A police officers boss
3. When i go from here to there quickly on foot

Idk thats what google said
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Can cells that are haploid (single set of chromosomes ) undergo meiosis
Dima020 [189]

Answer:

Yes they can

Haploid cells are mostly sex cells and these cells usually undergo meiosis.

Hope this helps.

5 0
3 years ago
How do anion formation and valence electrons relate?
vagabundo [1.1K]

Answer:

A cation is formed when a metal ion loses a valence electron while an anion is formed when a non-metal gains a valence electron. They both achieve a more stable electronic configuration through this exchange.

7 0
2 years ago
Read 2 more answers
A cylinder and piston assembly (defined as the system) is warmed by an external flame. The contents of the cylinder expand, doin
melomori [17]

Answer:

ΔE = 73 J

Explanation:

By the first law of thermodynamics, the energy in the system must conserved:

ΔE = Q - W

Where ΔE is the internal energy, Q is the heat flow (positive if it's absorbed by the system, and negative if the system loses heat), and W is the work (positive if the system is expanding, and negative if the system is compressing).

So, Q = + 551 J, and W = + 478 J

ΔE = 551 - 478

ΔE = 73 J

3 0
3 years ago
. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be r
Tom [10]

Answer :  The energy released by an electron in a mercury atom to produce a photon of this light must be, 4.56\times 10^{-19}J

Explanation : Given,

Wavelength = 435.8nm=435.8\times 10^{-9}m

conversion used : 1nm=10^{-9}m

Formula used :

E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

\nu = frequency

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength = 435.8\times 10^{-9}m

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{(435.8\times 10^{-9}m)}

E=4.56\times 10^{-19}J

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be, 4.56\times 10^{-19}J

3 0
3 years ago
What is the pH of 15 mL of .2 M HCl
fenix001 [56]
Easy peasy! All we need to do is plug this formula into our calculator:

-log(M)

So, we'd plug in -log(.2), which is 0.7 :)
3 0
3 years ago
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