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german
3 years ago
10

Assume that all of this fossil fuel is in the form of octane (C8H18) and calculate how much CO2 in kilograms is produced by worl

d fossil fuel combustion per year. (Hint: Begin by writing a balanced equation for the combustion of octane.) Express your answer using two significant figures.
Chemistry
1 answer:
AnnZ [28]3 years ago
5 0

The given question is incomplete. the complete question is:

The world burns the fossil fuel equivalent of approximately 9.50\times 10^{12} kg of petroleum per year. Assume that all of this petroleum is in the form of octane. Calculate how much CO2 in kilograms is produced by world fossil fuel combustion per year.( Hint: Begin by writing a balanced equation for the combustion of octane.)

Answer: 29\times 10^{12}kg

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2_C8H_{18}+17O_2\rightarrow 16CO_2+18H_2O

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of octane}=\frac{9.50\times 10^{12}\times 10^3g}{114g/mol}=0.083\times 10^{15}moles

According to stoichiometry :

As 2 moles of octane give = 16 moles of CO_2

Thus 0.083\times 10^{15}moles of octane give =\frac{16}{2}\times 0.083\times 10^{15}=0.664\times 10^{15}moles  of CO_2

Mass of CO_2=moles\times {\text {Molar mass}}=0.664\times 10^{15}moles\times 44g/mol=29.2\times 10^{15}g=29.2\times 10^{12}kg

Thus 29\times 10^{12}kg of CO_2 is produced by world fossil fuel combustion per year.

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Answer: 1. halve

2. halve

3. double

Explanation:

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E=\frac{hc}{\lambda}

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h = Planck's constant  

c = speed of light

Thus as wavelength and energy have inverse realation, when wavelength will halve , energy will double.

2. The between wavenumber and energy of the wave follows the equation:

E=h\times c\times \bar{\nu}

E= energy

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h = Planck's constant  

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Thus as wavenumber and energy have direct relation, when wavenumber will halve , energy will be halved.

3. The relationship between energy and frequency of the wave follows the equation:

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Thus as frequency and energy have direct realation, when frequency will double , energy will double.

3 0
3 years ago
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General representation of an element is given as:   _Z^A\textrm{X}

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The  balanced nuclear equation when the isotope Strontium-90 decays by Q-  decay is :

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3 0
3 years ago
Sterling silver is 92.5% silver and 7.5% copper. Its density is 10.25 g/cm3. A sterling silver pendant is added to a graduated c
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From the information given:

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∴

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Since, 1 mL = 1cm³

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Using the relation for Density; i.e.

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Recall that sterling silver has:

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The mass of the copper contained in the sterling silver pendant can be calculated as:

\mathbf{= \dfrac{115.825  \ g \times 7.5}{100}}

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Learn more about the relation between Density, Mass, and Volume here:

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