if a and b are directly proportional and the value of a becomes 1/4 as much ,what happens to the value of b
1 answer:
Answer:
Becomes 1/4 as much
Explanation:
If a and b are directly proportional, this means we may write an equality between them if some proportionality constant, k, is included, so that:
The equation shows that:
And since k is a constant, this would imply that increasing a by some fraction would also require b to increase by the same fraction.
In the context of this problem, we're given that a becomes 1/4 as much, meaning b should also become 1/4 as much to keep the same proportionality constant, k.
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Answer:
0.0714 M for the given variables
Explanation:
The question is missing some data, but one of the original questions regarding this problem provides the following data:
Mass of copper(II) acetate:
Volume of the sodium chromate solution:
Molarity of the sodium chromate solution:
Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:
Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:
Moles of the sodium chromate solution would be found by multiplying its volume by molarity:
Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.
Write the net ionic equation for this reaction:
Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:
According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:
The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate: