All categories

3 years ago

if a and b are directly proportional and the value of a becomes 1/4 as much ,what happens to the value of b

Chemistry

1 answer:

11Alexandr11 [23.1K]3 years ago

8 0

Answer:

Becomes 1/4 as much

Explanation:

If a and b are directly proportional, this means we may write an equality between them if some proportionality constant, k, is included, so that:

$a=kb$

The equation shows that:

$k=\frac{a}{b}$

And since k is a constant, this would imply that increasing a by some fraction would also require b to increase by the same fraction.

In the context of this problem, we're given that a becomes 1/4 as much, meaning b should also become 1/4 as much to keep the same proportionality constant, k.

You might be interested in

(a) Kw = 1.139 × 10⁻¹⁵ at 0°C and 5.474 × 10⁻¹⁴, find [H₃O⁺] and pH of water at 0°C and 50°C.

kondor19780726 [428]

The value of [H₃O⁺] and pH of water at 0°C and 50°C.

0°C value of [H₃O⁺] = 3.375 x 10⁻⁸

50°C value of [H₃O⁺] = 2.340 x 10⁻⁷

pH of water at 0°C = pH = 7.4717

pH of water at 50°C = pH = 6.6308

<h3>pH of water at different level:</h3>

Water with a pH less than 7 is considered acidic, while water with a pH greater than 7 is considered basic. The normal pH range for surface water systems is 6.5 to 8.5, and for groundwater systems is 6 to 8.5. Alkalinity is a measure of a water's ability to withstand a pH change that would cause it to become more acidic.

<h3>According to the given information:</h3>

0°C = Kw = 1.139 × 10⁻¹⁵

50°C = 5.474 × 10⁻¹⁴

Solving at 0°C for [H₃O⁺] and pH. water is neutral therefore its[H₃O⁺] [OH⁻]

are equal [H₃O⁺] = [OH⁻].

Kw = [H₃O⁺] [OH⁻]

Kw = [H₃O⁺]²

[H₃O⁺] = √Kw

= √1.139 × 10⁻¹⁵

= 3.375 x 10⁻⁸

pH = -log[H₃O⁺]

= -log 3.375 x 10⁻⁸

= 7.4717

Solving at 50°C for [H₃O⁺] and pH. water is neutral therefore its[H₃O⁺] [OH⁻]

are equal [H₃O⁺] = [OH⁻].

Kw = [H₃O⁺] [OH⁻]

Kw = [H₃O⁺]²

[H₃O⁺] = √Kw

= √ 5.474 × 10⁻¹⁴

= 2.340 x 10⁻⁷ M

pH = -log[H₃O⁺]

= -log2.340 x 10⁻⁷

pH = 6.6308

The value of [H₃O⁺] and pH of water at 0°C and 50°C.

0°C value of [H₃O⁺] = 3.375 x 10⁻⁸

50°C value of [H₃O⁺] = 2.340 x 10⁻⁷

pH of water at 0°C = pH = 7.4717

pH of water at 50°C = pH = 6.6308

To know more about pH of water visit:

brainly.com/question/13822050

#SPJ4

I understand that the question you are looking for is:

Kw = 1.139 × 10⁻¹⁵ at 0°C and 5.474 × 10⁻¹⁴, find [H₃O⁺] and pH of water at 0°C and 50°C. find the [H₃O⁺] and pH of water at 0°C and 50°C.

3 0

1 year ago

_Au2S3 + _H2---> _Au + _H2S

timofeeve [1]

The answer is A because if you place the first two numbers 1 and 3
Au=2
S=3
H=6
It has to equal to the product so then you put in the last two numbers 2 and 3
Au=2
S=3
H=6

4 0

3 years ago

Read 2 more answers

Convert 7.1x10^25 molecules of water to moles

ruslelena [56]

Answer:

<h2>117.94 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{7.1 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 117.940199...$

We have the final answer as

<h3>117.94 moles</h3>

Hope this helps you

8 0

3 years ago

Look at the four chemical reactions.

frutty [35]

Reaction 3 is different from the rest and it is because a single product is synthesized.

Option 2

<u>Explanation:</u>

The reaction given in 1,2 and 4 are dissociation reaction where a single compound is getting split into two compounds. So all those three reactions are exothermic as they are breaking the bonds leading to release of energy to the surrounding. But the reaction 3 is a formation reaction, where two chemical compounds are forming a single compound.

So in this case, new bonds are formed leading to absorption of energy from the surrounding. So this is an endothermic reaction. Thus, reaction 3 is different from the rest and it is because a single product is synthesized.

8 0

3 years ago

what are the names of the "subunits" within the myofibrils that run the length of skeletal muscle fibers?

Shtirlitz [24]

Answer:

Sarcomeres

Explanation:

A muscle fiber is composed of many myofibrils, A sarcomere is the basic unit of a myofibril.

Sarcomeres are arranged in a stacked pattern throughout the muscle tissue, giving it a striped pattern. Sarcomeres are composed of thick and thin filaments. The thin and thick filaments interact initiate the movement of muscle.

6 0

3 years ago