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ahrayia [7]
3 years ago
10

if a and b are directly proportional and the value of a becomes 1/4 as much ,what happens to the value of b

Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

Becomes 1/4 as much

Explanation:

If a and b are directly proportional, this means we may write an equality between them if some proportionality constant, k, is included, so that:

a=kb

The equation shows that:

k=\frac{a}{b}

And since k is a constant, this would imply that increasing a by some fraction would also require b to increase by the same fraction.

In the context of this problem, we're given that a becomes 1/4 as much, meaning b should also become 1/4 as much to keep the same proportionality constant, k.

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Since the 6s orbital with one electron is contracted, this electron is more tightly bound to the nucleus and less available for bonding with other atoms. The 4f and 5d orbitals expand, but can't be involved in bond formation since they are completely filled. This is why gold is relatively unreactive.

Hope it helps

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3 years ago
Write the net ionic equation for the precipitation of calcium sulfide from aqueous solution
Fantom [35]

Answer:

Answer is Ca2+(aq)+S2-(aq)=>CaS(s)

Explanation:

I hope it's helpful!

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True or false natural elements don't reflect light.
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Describe the process of crystallization.
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2 years ago
Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.
Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

T = 1 * 40 + 2 * 1 + 2 * 16

T = 74

The amount of calcium is: (i.e formula mass of calcium)

E = 1 * Ca

E = 1 * 40

E = 40

So, the percentage component of calcium is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{40}{74} * 100\%

\%C_E = \frac{4000}{74}\%

\%C_E = 54.05\%

The amount of hydrogen is:

E = 2 * H

E = 2 * 1

E = 2

So, the percentage component of hydrogen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{2}{74} * 100\%

\%C_E = \frac{200}{74}\%

\%C_E = 2.70\%

Similarly, for oxygen:

The amount of oxygen is:

E = 2 * O

E = 2 * 16

E = 32

So, the percentage component of oxygen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

5 0
3 years ago
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