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What can you say about the impedance of a series RLC circuit at the resonant frequency? The impedance of a series RLC circuit is
2 answers:
Answer:
At resonance impedance of series RLC circuit is minimum and equal to resistance of the circuit
Explanation:
Let the resistance of the series RLC circuit is R
Capacitive reactance of the circuit is and inductive reactance of the circuit is
We know that impedance of the series RLC circuit is given by , here R is the resistance
is inductive reactance and
is capacitive reactance
At resonance capacitive reactance will be equal to inductive reactance
So
So impedance will become
So from above calculation we can say that impedance of series RLC circuit is minimum and equal to resistance of the circuit
Answer:
Explanation:
Let R is the resistance of the circuit, L is the inductance of the circuit and c is the capacitance.
Inductive reactance= XL
capacitive reactance = Xc
The impedance of the RLC circuit is
As the circuit is in resonance, So, XL = Xc
In this condition, Z = R
So, the impedance is equal to the resistance of the circuit.
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Answer:
fundamental frequency= 20Hz
length= 4.3m
Explanation:
resonating frequencies = 60 Hz,100 Hz,140 Hz
speed of sound =344 m/s
as well behaves as organ pipe with are end closed
only odd harmonics are allowed
, so the vibration will corresponds to n=1,3,5,7....
(2n−1) λ
/4 = l (∵λ
= V/f)
(2n-1) V / 4f = l
(2m-1)/6= (2n-1)/10= (2p-1)/14 =A
The given frequencies happen to be 3rd,5th & 7th harmonics of the fundamental frequency n=20Hz.
Therefore, The fundamental frequency will be 20 Hz because 60 Hz is corresponding 3rd harmonic
In order to find length,
(2n-1) V / 4f = l
= 4.3m
therefore, the well is 4.3m deep
The spring-mass system moves by simple harmonic motion, where there is a continuous conversion from elastic potential energy to kinetic energy and viceversa.
The total mechanical energy of the system at any moment of the motion is
where the first term U is the elastic potential energy, with k being the spring constant and x the displacement of the spring with respect to its rest position, and the second term K is the kinetic energy, with m being the mass of the object attached to the spring and v its speed.
The total energy E is constant during the oscillation of the spring, but the values of U and K change. In fact, when the displacement of the spring is maximum (x is maximum), then all the energy is potential energy U, because the speed of the object is zero (it's the moment when the mass is changing direction). On the contrary, when the mass crosses the equilibrium position (rest position) of the spring, then the potential energy is zero (U=0) because the displacement is zero (x=0), and so all the energy is kinetic energy of the motion, and so K is maximum.
The total mechanical energy of the system at any moment of the motion is
where the first term U is the elastic potential energy, with k being the spring constant and x the displacement of the spring with respect to its rest position, and the second term K is the kinetic energy, with m being the mass of the object attached to the spring and v its speed.
The total energy E is constant during the oscillation of the spring, but the values of U and K change. In fact, when the displacement of the spring is maximum (x is maximum), then all the energy is potential energy U, because the speed of the object is zero (it's the moment when the mass is changing direction). On the contrary, when the mass crosses the equilibrium position (rest position) of the spring, then the potential energy is zero (U=0) because the displacement is zero (x=0), and so all the energy is kinetic energy of the motion, and so K is maximum.