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nikitadnepr [17]
3 years ago
10

What can you say about the impedance of a series RLC circuit at the resonant frequency? The impedance of a series RLC circuit is

maximum in magnitude at the resonant frequency and is equal to the resistance.
Physics
2 answers:
Svet_ta [14]3 years ago
7 0

Answer:

At resonance impedance of series RLC circuit is minimum and equal to resistance of the circuit

Explanation:

Let the resistance of the series RLC circuit is R

Capacitive reactance of the circuit is X_C and inductive reactance of the circuit is X_l

We know that impedance of the series RLC circuit is given by Z=\sqrt{R^2+(X_L-X_C)^2}, here R is the resistance X_l is inductive reactance and X_C is capacitive reactance

At resonance capacitive reactance will be equal to inductive reactance

So X_C=X_l

So impedance will become Z=R

So from above calculation we can say that impedance of series RLC circuit is minimum and equal to resistance of the circuit

Katyanochek1 [597]3 years ago
6 0

Answer:

Explanation:

Let R is the resistance of the circuit, L is the inductance of the circuit and c is the capacitance.

Inductive reactance= XL

capacitive reactance = Xc

The impedance of the RLC circuit is

Z=\sqrt{R^{2}+\left ( X_{L}^{2}-X_{C}^2 \right )}

As the circuit is in resonance, So, XL = Xc

In this condition, Z = R

So, the impedance is equal to the resistance of the circuit.  

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Why does the current splits in parallel circuit and why does the voltage remains equal?​
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<u>Voltage:</u>

It is basically the difference between the charges of the materials on the ends of the Wire

<em>also known as potential difference</em>

It is very similar to the movement of air, it moves from higher density to lower density. in this case, the change in density is the potential difference

So, since voltage is the difference between the charge available on the ends of a wire. Even if the wire splits in parallel circuit, the difference of the charges remains the same

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<u>Current:</u>

Current is the amount of electrons moving through a cross-section of a wire in a period of time

So basically, it is the amount of electrons that move across a given point on a wire in a period of time

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3 0
2 years ago
When a 12 N horizontal force is applied to a box on a horizontal tabletop, the box remains at rest. The force of friction acting
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Answer:

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Explanation:

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F = ma ........................Equation 1

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making a the subject of the equation,

a = F/m.................... Equation 2

Given: F = 4.0×10⁻¹⁵ N,

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Substituting into equation 2

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7 0
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