Answer:
Explanation:
Hello,
In case, for the boiling point raise we can write:
Whereas T2 accounts for the boiling point of the solution which is 101.286 °C, T1 the volume of pure water which is 100.000 °C, i the van't Hoff factor that for this problem is 1 due to the solute's non-volatility, m the molality of the solute and Kb the boiling point constant that is 0.512 °C/m. In such a way, the change in the temperature is:
The molality is computed from the boiling point raise:
The moles are computed by multiplying the molality by the kilograms of water as the solvent (0.02002g):
And the molecular mass by dividing the mass of the solute by its moles:
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<u>Answer:</u> The correct statement is B will give up two electrons to form bonds.
<u>Explanation:</u>
We are given:
Number of electrons in Atom A = 10
Number of electrons in Atom B = 12
Writing the electronic configuration for both the atoms:
For A:
For B:
From the configuration, it is clearly visible that the configuration of Atom A is stable and this atom will neither gain or loose electrons to attain stability.
Atom B has 2 valence electrons and by loosing these 2 electrons, it will attain stable electronic configuration and form ion. Atom B will bond after loosing 2 electrons.
Hence, the correct statement is B will give up two electrons to form bonds.
When
Aldehyde is reacted with
Alcohol in the presence of
acid the it gives
Hemiacetal, Hemiacetal on further reaction with acid and alcohol gives
Acetal.
In given problem the aldehyde given is
P<span>
henylacetaldehyde and alcohol is
Methanol. The reaction is done stepwise as shown below,</span>
The gravitational pull of the sun and the moon combined is ceeating a larger than normal tide