1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mkey [24]
3 years ago
14

What is the most believable part of the big bang theory?

Chemistry
1 answer:
Fantom [35]3 years ago
5 0

Answer:

the exploshion

Explanation:

<h2>ra[e urs HAHAHA</h2>
You might be interested in
List the elements of carbon
kap26 [50]

Answer:

Explanation:

Carbon group element, any of the six chemical elements that make up Group 14 (IVa) of the periodic table—namely, carbon (C), silicon (Si), germanium (Ge), tin (Sn), lead (Pb), and flerovium (Fl).

Elements: Lead; Germanium; Silicon; Tin; Carbon,silicon,germanium,tin,lead,and flerovium

5 0
4 years ago
(40 Points) Complete, balance, compute the amounts of the products assuming 100% yield. 10g Na + 10g Oxygen.
Lilit [14]

13.5g

Explanation:

Given parameters:

Mass of Na = 10g

Mass of O₂ = 10g

Unknown:

Mass of products formed = ?

Balanced equation = ?

Solution:

The balanced chemical equation is shown below:

                  4Na       +     O₂     ⇒      2Na₂O

In any reaction, the specie in short supply determines the extent of the reaction.

This reaction is not an exclusion. We need to first determine the specie in short supply and use it to estimate the amount of product since we have a 100% yield which signifies that all was used up.

  let us convert to moles;

    Number of moles of Na = \frac{mass }{molar mass}  = \frac{10}{23} = 0.435mole

 Number of moles of O₂ = \frac{mass}{molar mass} = \frac{10}{32} = 0.313mole

From the given equation;

   4 moles of Na requires 1 mole of O₂;

  0.435 moles of Na will require \frac{0.435}{4} = 0.11 moles

 But the given amount O₂ is 0.313, this is an excess of 0.313 - 0.11 = 0.203moles

We see that Na is the limiting reagent;

   4 moles of Na gives 2 mole of Na₂O

   0.435 moles of Na will give \frac{0.435 x 2 }{4} = 0.22 moles

Mass of Na₂O = number of moles x molar mass = 62 x 0.22 = 13.5g

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

5 0
4 years ago
Which phase of matter consists of ionized particles that move independently of each other/10900502/4a93e3cd?utm_source=registrat
vlada-n [284]
The answer is.............................................. plasma
7 0
4 years ago
Write a balanced chemical equation for the photosynthesis reaction in which gaseous carbon dioxide and liquid water react in the
sasho [114]
6 CO₂ + 6 H₂O (chlorophyll + sunlight) ⇒ C₆H₁₂O₆ + 6 O₂ 
the reaction takes place in presence of sunlight and chlorophyll .. 
CO₂ is oxidized and forms Glucose . And oxygen is evolved in this process. 

3 0
3 years ago
The compounds that form from the bonding of the hydroxyl group (-OH) to a hydrocarbon are called the aldehydes.
hoa [83]

Answer:

True

Explanation:

4 0
3 years ago
Read 2 more answers
Other questions:
  • WILL MARK YOU THE BRAINLIEST IF YOU ANSWER THESE TWO QUESTION CORRECTLY :)
    8·1 answer
  • What solid can be formed from a net diagram that has 2 congruent circles and 1 rectangle?
    8·2 answers
  • What is the molarity of a solution containing 9.0 moles of solute in 2500 mL of solution?
    7·1 answer
  • How many moles of water, H2O, contain 2.0×1022 molecules of water
    9·1 answer
  • In the reaction A + B + C &gt;&gt; D, what are the products?
    8·1 answer
  • If I have 7.7 moles of gas at a pressure of 0.0990 ATM and at a temperature of 256 K, what is the volume of the container that t
    6·1 answer
  • Match each term with the appropriate definition.
    11·1 answer
  • QuesLIUI 11 point)
    8·1 answer
  • Which part of the red blood cells can you find hemoglobin​
    6·1 answer
  • Nitrogen dioxide, a major air pollutant, can be produced by the combustion of nitrogen oxide as shown. 2NO O2 Right arrow. 2NO2
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!