Answer:
24.58 m/s
Explanation:
Given that,
Speed of an object = 55 mph
We need to find the equivalent unit in m/s
We know that,
1 mile = 1609 m
1 hour = 3600 s
So,

So, the required speed is 24.58 m/s.
Answer:
The answer to your question is:
Explanation:
Data
Atomic number = Z = 28
Mass number = A = 152
Atomic number number = # of protons
Mass number = # of protons + # of neutrons
Then
Protons = 28
Electrons = 28
Neutrons = 152 - 28 = 124
<u>Mendeleev </u><u>positioned elements in the periodic table in</u><u> increasing order </u><u>of their atomic numbers, such that </u><u>elements </u><u>having identical chemical properties and characteristics plunge into the </u><u>same group.</u>
What is Mendeleev's periodic table called?
- In order to represent similarities and patterns in the behavior of elements, Mendeleev created the periodic table, which is an arrangement of elements in an increasing atomic mass order in tablet form.
- Mendeleev stated that "Element characteristics are a periodic function of their atomic weight" in his renowned periodic law.
- The Periodic Table of Mendeleev is a table that Mendeleev created to list elements in the order of their atomic weights.
- Mendeleev discovered that there were two elements with atomic weights between 65.2 and 75 because he found it very satisfying that the properties of the elements were more similar and closer to this level.
- He also imagined having other elements with possessions similar to those of these other elements.
- In the periodic table, he left a blank for these two elements until they were finally discovered in their true existence.
Learn more about Mendeleev's periodic table
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Answer:
44.91% of Oxygen in Iron (III) hydroxide
Explanation:
To solve this question we must find the molar mass of Fe(OH)3 and the molar mass of the oxygen in this molecule. Percent composition will be:
<em>Molar mass Oxygen / molar mass Fe(OH)3 * 100</em>
<em />
<em>Molar mass Fe(OH)3 and oxygen:</em>
1Fe = 55.845g/mol*1 = 55.845
3O = 16.00g/mol*3 = 48.00 - Molar mass of Oxygen
3H = 1.008g/mol*3 = 3.024
55.845 + 48.00 + 3.024 =
106.869g/mol is molar mass of Fe(OH)3
% Composition of oxygen is:
48.00g/mol / 106.869g/mol * 100 =
<h3>44.91% of Oxygen in Iron (III) hydroxide</h3>
The bubbles that were observed after the mixing of the two substances is one of the products of the reaction. It is the carbon dioxide that is produced. To determine the mass of this gas produced, we need to remember the Law of conservation of mass where mass cannot be created or destroyed. With this, we can say that the total mass that goes in a process should be equal to the mass that is goes out of the process no matter what the reaction is. We do as follows:
Mass of reactants = mass of products
11.00 + 44.55 = 51.04 + mass of carbon dioxide
mass of carbon dioxide = 4.51 g