<u>Answer:</u>
<em>To raise the pH of the solution to 3.10 we have to add 2.34 L of water.</em>
<u>Explanation:</u>
<em>Given that the pH of the solution of HCl in water is 2.5.</em> Here the solution’s pH is changing from 2.5 to 3.10 which means the acidic nature of the solution is decreasing here on dilution.
ions contribute to a solution’s acidic nature and
contribute to a solution’s basic nature.
The equation connecting the concentration of
and pH of a solution is pH= ![-log[H^+]](https://tex.z-dn.net/?f=-log%5BH%5E%2B%5D)
<em>![[H^+]= 10^(^-^p^H^)](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%2010%5E%28%5E-%5Ep%5EH%5E%29)
</em>
<em>When the pH is
</em>
<em>On dilution the concentration of a solution decreases and volume increases.</em>
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<em>Volume of water to be added
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Answer:
Matter is classified into two broad categories, namely, pure substances and mixtures. Mixtures can be separated into pure substances by physical methods. Pure substances are further divided into categories as elements and compounds. ... A pure substance can be either an element or a compound.
Explanation:
I believe the answer is 4 carbons. Glycolysis involves break down of glucose to two molecules of pyruvic acid (3 carbons) under aerobic conditions. At the end of glycolysis the two pyruvate molecules undergoes pyruvate oxidation to capture the remaining energy in the form of ATP. A carboxyl group is removed from pyruvate and released in the form carbon dioxide, leaving a two carbon molecule which forms Acetyl-CoA (2 molecules). Acetyl-CoA then serves as a fuel for the citric acid cycle in the next stage of cellular respiration.
Answer:
Anhydride, any chemical compound obtained, either in practice or in principle, by the elimination of water from another compound. Examples of inorganic anhydrides are sulfur trioxide, SO3, which is derived from sulfuric acid, and calcium oxide, CaO, derived from calcium hydroxide
Explanation:
<h3>
<em><u>examples</u></em><em><u>.</u></em></h3>
1)acid anhydride.
2)basic anhydrides.
<h3>
<em><u>reactions</u></em><em><u>. </u></em></h3>
1)reaction with water
(CH3CO)2O + H2O → 2 CH3CO2H.
Answer:
the volume of the sound will quarter
Explanation:
As you move far away from the source, the loudness of sound decreases. This is because as the distance from the source increases, the area it covers also increases thereby spreading the energy over a great area leading to lesser loudness and intensity.
As a result of this, sound intensity follows an inverse square law:
I ∝ 1/d²; where I is the intensity and d is the distance from source.
Therefore If a speaker is moved from 2 feet away to 4 feet away (increment of 2 feet), the volume of the sound would quarter (1/2² = 1/4)