Answer:
c = 13
m∡A = 60°
m∡B = 30°
Step-by-step explanation:
This is a 5-12-13 triangle. However, to make sure, I will put the steps.
Allow for each sides to be denoted as a-b-c, in which c is the hypotenuse (longest side). Set the equation:
a² + b² = c²
Plug in the corresponding numbers to the corresponding variables:
5² + 12² = c²
Simplify. First, solve the exponents, and then add:
(5²) = 5 * 5 = 25
(12²) = 12 * 12 = 144
25 + 144 = c²
c² = 169
Note the equal sign, what you do to one side, you do to the other. Isolate the variable, c, by rooting both sides:
√c² = √169
c = √169 = √(13 * 13) = 13
c = 13
13 is your answer for c.
Note the measurements of the angles. We know that this is a 30-60-90 triangle, and so it will be easy to figure it out. Note that the corresponding angles will depend on that of the opposite side's measurement lengths. The hypotenuse will always be on the opposite side of the largest angle (as given), as c, the longest side, is opposite of ∡C, which is the largest angle (90°). Based on this information, it means that ∡A would be 60° (as it is opposite of the middle number, 12), and ∡B would be 30° (opposite of the smallest number, 5).
Answer:
the exact answer would be 651
Step-by-step explanation:
if you were to estimate I would say you should probably round up to 700
Given:
right triangle
a = 2.9
c = 4.2
Pythagorean Theorem: a² + b² = c²
missing value of b.
b² = c² - a²
b² = (4.2)² - (2.9)²
b² = 17.64 - 8.41
b² = 9.23
b = √9.23
b = 3.03 or 3.0
The value of b is 3.0
Answer:
The value of x in the 2nd quadrant is always negative.
Step-by-step explanation:
There form four zones in the coordinate plane by placing the coordinate axes i.e. X-axis and Y-axis. The top right zone is called the 1st quadrant and 2nd, 3rd and 4th quadrants are the zones obtained by rotating in anticlockwise about the origin.
Since the 2nd quadrant is placed at the top left zone, so, we have to move in the negative x-direction along or parallel to the X-axis and to move in the positive y-direction along or parallel to the Y-axis.
Therefore, the value of x in the 2nd quadrant is always negative.
(Answer)