<span>C.) When interest compounds quarterly</span>
Answer:
Step-by-step explanation:
grampa gump=gg
junior gump=jg
gg/16=jg
jg=5
gg/16=5
gg=80 years old
The solution of the equation is x= 3 and y = 2
Step-by-step explanation:
Given,
-3x-4y = -17 and
-x-3y = -9
The system of equation can be rewritten as
3x+4y = 17 ------eq 1 and
x+3y = 9 ------ eq 2
To solve for x and y
Multiplying eq 2 by 3 we get,
3x + 9y = 27
or, 3x = 27-9y
Putting this value of x into eq 1 we get,
27-9y +4y = 17
or, -5y = 17-27
or, -5y = -10
or, y = 2
Now put y=2 in eq 2 we get,
x = 9 - 3(2)
= 3
Hence the solution is x = 3 and y = 2
Answer
(C) y +5 =3(x+4)
We will use the point-slope formula to solve this problem.
We will use the point-slope formula to solve this problem.(y+5)=3(x+4)
)Explanation:
)Explanation:We can use the point slope formula to solve this problem.
)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)
)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)Where m is the slope and (x1y1) is a point the line passes through.
)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)Where m is the slope and (x1y1) is a point the line passes through.We can substitute the slope and point we were given into this formula to produce the equation we are looking for:
)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)Where m is the slope and (x1y1) is a point the line passes through.We can substitute the slope and point we were given into this formula to produce the equation we are looking for:(y−(−5))=3(x--(4))
=> (<u>y+</u><u>5</u><u>)=3(x</u><u>+</u><u>4</u><u>)</u>
2(5x-15) + 2(2x+7) =0
10x-30+4x+14 = 0
14x = 16
x = 8/7
