Ask question

Ask question

All categories

3 years ago

8

A synthetically-produced narcotic medication, drug, or agent similar to the opiate morphine, but not derived from opium; used to

relieve pain

1 answer:

Otrada [13]3 years ago

4 0

A synthetically-produced narcotic medication, drug, or agent similar to the opiate morphine, but not derived from opium; used to relieve pain
Yes

You might be interested in

The image shows the representation of an unknown element in the periodic table. A square is shown. Inside the square twelve is w

avanturin [10]

Answer:

The combined mass of all the protons and electrons is 24.305.

Explanation:

From the information given about the atom, we can see that the relative atom mass of the element is 24.305.

The relative atomic mass of an atom is the combined mass of all its isotope in proportion of their geonormal abundances. On the periodic table, this mass deals with the amount of protons and neutrons present in a given atom.

7 0

3 years ago

Consider the rate law below.

Serga [27]

C. quadruples the rate

<h3>Further explanation</h3>

Given

The rate law :

R=k[A]²

Required

The rate

Solution

There are several factors that influence reaction kinetics :

1. Concentration
2. Surface area
3. Temperature
4. Catalyst
5. Pressure
6. Stirring

The rate is proportional to the concentration.

If the concentration increased, the reaction rate will increase

The reaction is second-order overall(The exponent is 2)

The concentration of A is doubled, the reaction rate will increase :

r = k[A]² ⇒ r= k[2A]²⇒r=4k[A]²

<em>The reaction rate will quadruple.</em>

5 0

3 years ago

The density of an aqueous solution of nitric acid is 1.64 g/mL and the concentration is 1.85 M. What is the concentration of thi

galina1969 [7]

Answer:

Mass % of the solution = 7.1067 %

Explanation:

Given :

Molarity of nitric acid solution = 1.85 M

Density of the solution = 1.64 g/mL

<u>Molarity of a solution is defined as the number of moles of solute present in 1 liter of the solution.</u>

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Lets, consider the volume of the solution = 1 L

Thus,

Moles of nitric acid present in the solution:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles of Nitric acid=Molarity \times {Volume\ of\ the\ solution}$

So,

Moles of Nitric acid = 1.85 moles

Molar mass of nitric acid = 63 g/mol

The mass of Nitric acid can be find out by using mole formula as:

$moles=\frac{Mass\ taken}{Molar\ mass}$

Thus,

$Mass\ of\ Nitric\ acid=Moles \times Molar mass}$

$Mass\ of\ Nitric\ acid=1.85 g \times 63 g/mol}$

<u>Mass of Nitric acid = 116.55 g</u>

Also,

$Density=\frac{Mass}{Volume}$

Given : Density = 1.64 g/mL

Also, 1 L = 10³ mL

Volume of the solution is 1000 mL

So, mass of the solution:

$Mass\ of\ the\ solution=Density \times {Volume\ of\ the\ solution}$

$Mass\ of\ the\ solution=1.64 g/mL \times {1000 mL}$

<u>Mass of the solution = 1640 g</u>

Mass % is defined as the mass of solute in 100 g of the solution. The formula for the calculation of mass % is shown below:

$Mass \% =\frac{Mass\ of\ the\ solute}{Mass\ of\ the\ solution} \times {100}$

So,

$Mass \%=\frac{116.55}{1640} \times {100}$

<u>Mass % = 7.1067 %</u>

6 0

3 years ago

Pani-rosa [81]

Answer:

$b.$ $obtain$

Explanation:

Let us look at all the answers definitions,

Sponsor would not work as it talks about a company offering you something in back for an advertisement.

Obtain would work as it means to acquire something.

Neglect would not work because it means to fail to care for something properly

Dismiss wouldn't work because it means to leave or allow to exit

5 0

3 years ago

What happens to the H20 in a combustion reaction?

allochka39001 [22]

A combustion reaction is when a substance reacts with oxygen and releases a huge amount of energy in the form of light and heat. A combustion reaction always has oxygen as one reactant. ... A combustion reaction also always produces CO2 and H2O.

So water (H2O) is created

Source: https://study.com/academy/lesson/writing-and-balancing-combustion-reactions.html

6 0

3 years ago