Answer:
They have properties of both metals and nonmetals
Explanation:
- Elements in the periodic table may be divided into Metals, non-metals, and metalloids.
- Metals are the elements that react by losing electrons to form stable positively charged ions known as cations. Examples are group 1, 2, and 3 elements together with transition elements.
- Non-metals are those elements that react by gaining electrons to form stable negatively charged ions called anions. Examples include oxygen, carbon, sulfur, etc.
- Metalloids, on the other hand, are elements that have both metallic and non-metallic properties.
- Metalloids occur between metals and non-metals in the periodic table. Examples include Boron and silicon among others.
Answer:
0.11M
Explanation:
What is the Molarity of a Ca(OH)2 solution if 30.0mL of
the solution is neutralized by 26.4mL of 0.25M HCI solution?
1L (1000 ml) of the HCl contains 0.25 moles of H ion
26.4 ml contains ( 26.4 X0.25/1000) moles of H ion ion
=0.0066 moles H ion
2HCl +Ca (OH)2-----> 2H2O +CaCl2
SO 2 H IONS NEUTRALIZE 1 Ca(OH)2 MOLECULE
00066 moles H ion neutralize 0.0033 moles Ca(OH)2
the 0.0033 moles are distributed over 30 ml, so the concentration of the
Ca(OH)2 IS 0,0033/(30/1000) =0.11 moles/liter or 0.11M
Answer:
um...
Explanation:
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(4 mol H2O) x (112 kJ / 3 mol H2O) = 149 kJ
<span>(14.5 g HCl) / (36.4611 g HCl/mol) x (112 kJ / 3 mol HCl) = 14.9 kJ </span>
<span>(475 kJ) / (181 kJ / 2 mol HgO) x (216.5894 g HgO/mol) = 1137 g HgO </span>
<span>(179 kJ) / (181 kJ / 1 mol O2) x (31.99886 g O2/mol) = 31.6 g O2 </span>
<span>(145 kJ) / (112 kJ / 3 mol Cl2) x (70.9064 g Cl2/mol) = 275 g Cl2 </span>
<span>(14.5 g S2Cl2) / (135.0360 g S2Cl2/mol) x (112 kJ / 1 mol S2Cl2) = 12.0 kJ </span>
<span>CaCO3 + 2 NH3 → CaCN2 + 3 H2O; ∆H = –90.0 kJ </span>
<span>(798 kJ) / (90.0 kJ / 2 mol HN3) x (17.03056 g NH3/mol) = 302 g NH3 </span>
<span>(19.7 g H2O) / (18.01532 g H2O/mol) x (90.0 kJ / 3 mol H2O) = 32.8 kJ</span>
