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allsm [11]
3 years ago
13

An oxygen atom has a mass of 2.66 x 10^-23 g and a glass of water has a mass of 0.050kg. Use this information to answer the ques

tions below. Be sure your answers have the correct number of significant digits.
What is the mass of 1 mole of oxygen atoms?
How many moles of oxygen atoms have a mass equal to the mass of a glass of water?
Chemistry
1 answer:
fomenos3 years ago
3 0
<h2>ANSWER OF EACH PART ARE GIVEN BELOW</h2>

Explanation:

A)

We know, each mole contains N_A= 6.023 \times 10^{23} atoms.

It is given that mass of one oxygen atom is m= 2.66\times 10^{-23}\ g.

Therefore, mass of one mole of oxygen, M=m\times N_A.

Putting value of n and N_A,

M=2.66\times 10^{-23}\times 6.023\times 10^{23} \ gm\\M=16.0\ gm

B)

Given,

Mass of water in glass=0.050 kg = 50 gm.

From above part mass of one mole of oxygen atoms = 16.0 gm.

Therefore, number of mole of oxygen equivalent to 50 gm oxygen=\dfrac{50}{16}=3.1 \ moles.

LEARN MORE :

Avogadro's number

brainly.com/question/12902286

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Are elements considered to be substances?
Schach [20]

Answer:

C. Yes, because they have a definite composition.

Explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
7 0
3 years ago
HELP ASAP!! PLZ
Schach [20]

D. The empirical formula and the molar mass

8 0
2 years ago
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What are the various ways in which an atom of an element can achieve the noble gas configuration ? ​
azamat

Answer:

<h3><em>Atoms attain noble gas configuration </em><em> by obtaining or donating and sharing of electrons present in their outermost shell.</em><em> </em></h3>
7 0
2 years ago
How many mols of chlorine are in 120g of chlorine gas
xz_007 [3.2K]

Answer:

Number of moles of chlorine = 3.38 mol

Explanation:

Given data:

Mass of chlorine = 120 g

Moles of chlorine = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of chlorine = 35.5 g/mol

Now we will put the values in formula.

Number of moles = 120 g/ 35.5 g/mol

Number of moles = 3.38 mol

6 0
3 years ago
A sample of helium has a volume of 5 liters and a pressure of 699 mmHg. If the final volume is 5.7 Liters, its final temperature
malfutka [58]

Answer:

The initial temperature of helium was T1 = 232.23 K

Explanation:

Given data:

Initial volume V1 = 5 L

Initial pressure P1 = 699 mmHg

Final pressure P2 = 800 mmHg

Final volume V2 = 5.7 L

Final temperature T2= 303 K

Initial temperature T1 = ?

Solution:

Formula:

P1V1/T1 = P2V2/T2

T1 = T2 × P1V1/P2V2

T1 = 303 K × 699 mmHg × 5 L / 800 mmHg × 5.7 L

T1 = 1058985/ 4560

T1 = 232.23 K

initial temperature of helium was 232.23 k.

6 0
3 years ago
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