Question

A rectangular weir is in a rectangular channel 2.9 m wide. The length of the weir is 1.9 m and is centered in the channel. If the water level is 0.2 m above the surface of the weir, what is the discharge in the channel (m3/sec)

Answer 1

Answer:

discharge = 0.310976 m³/s

Explanation:

given data

rectangular channel  wide = 2.9 m

length of weir L = 1.9 m

water level H = 0.2 m

solution

we get here discharge that is express as

discharge = $\frac{2}{3} * C_d * L* \sqrt{2g} * H^{\frac{3}{2} }$    ............................1

we consider here Coefficient of discharge Cd = 0.62

put here value we get

discharge = $\frac{2}{3} * 0.62 * 1.9* \sqrt{2*9.8} * 0.2^{\frac{3}{2} }$

discharge = 0.310976 m³/s