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4 years ago

In poor weather, you should __ your following distance

Engineering

2 answers:

Ratling [72]4 years ago

5 0

Answer:

I think reduce your following distance

olganol [36]4 years ago

4 0

｡☆✼★ ━━━━━━━━━━━━━━━ ☾

Following distance is how much distance there is between your car and the car in front

If there is poor weather, it is said that you should increase your following distance to prevent accidents.

Thus, your answer is A

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

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The C language allows developers to pass functions as parameters to other functions. Provide a declaration for a function named

MariettaO [177]

Answer:

answer is given below

Explanation:

Declaration for garnet

void garnet(char,int (*f)(int));

void - garnet return nothing

garnet accepts two parameters

'Char'
function

Function as a parameter

int (*f) (int))

and here

first int refers return type of function

(*f) function as pointer variable

second int

arguments that accept by inner function- function as a parameter

so here Garnet is a function that accepts two parameters. One parameter that contains the character and another parameter that takes an argument (here I am taking an integer) and returns an integer. Function The function returns nothing. Zero is mentioned here.

5 0

4 years ago

Which of the following is the next “up-and-coming” digital publishing industry?

storchak [24]

Answer:

3D printing

Explanation:

The developments in technology, infrastructure, systems and technology mean that 3D printing will soon become a production technology. The market penetration of 3D printing would inevitably rise over time, with certain categories almost completely transitioning to 3D printing, such as digital publishing.

6 0

3 years ago

A hole of diameter D = 0.25 m is drilled through the center of a solid block of square cross section with w = 1 m on a side. The

attashe74 [19]

Answer:

$q=4.013\:\:kW\\\\T_1=278.91\:\:^{\circ}C\\\\T_2=275.82\:\:^{\circ}C$

Explanation:

$R_{conv,1}=(h_1\pi D_1L)^{-1}=(50*0.25*2)^{-1}=0.01273\:\:K/W\\\\R_{conv,2}=(h^2*4wL)^{-1}=(4*4*1)^{-1}=0.0625\:\:K/W\\\\R_{cond(2D)}=(Sk)^{-1}=(8.59*150)^{-1}=0.00078\:\:K/W$

So, heat rate can be calculated as follows:

$q=\frac{T_{\infty,1}-T_{\infty,2}}{R_{conv,1}+R_{conv,2}+R_{cond(2D)}} =\frac{330-25}{0.076} =4.013\:\:kW$

Surface temperatures can be calculated as follows:

$T_1=T_{\infty,1}-qR_{conv,1}=330-51.09=278.91\:\:^{\circ}C\\\\T_2=T_{\infty,2}+qR_{conv,2}=25+250.82=275.82\:\:^{\circ}C$

6 0

4 years ago

An engineer designing a hydroelectric facility recalls that the flow rate (in gallons per second) is four times the value of the

GarryVolchara [31]

Answer:

Flow rate = 86.48 gal/s

Head of water = 21.62 ft

Explanation:

Detailed explanation and calculation is shown in the image below.

7 0

4 years ago

Read 2 more answers

A counter-flow double-piped heat exchange is to heat water from 20oC to 80oC at a rate of 1.2 kg/s. The heating is to be accompl

lawyer [7]

Answer:

110 m or 11,000 cm

Explanation:

let mass flow rate for cold and hot fluid = Mc and Mh respectively
let specific heat for cold and hot fluid = Cpc and Cph respectively
let heat capacity rate for cold and hot fluid = Cc and Ch respectively

Mc = 1.2 kg/s and Mh = 2 kg/s

Cpc = 4.18 kj/kg °c and Cph = 4.31 kj/kg °c

Using effectiveness-NUT method

First, we need to determine heat capacity rate for cold and hot fluid, and determine the dimensionless heat capacity rate

Cc = Mc × Cpc = 1.2 kg/s × 4.18 kj/kg °c = 5.016 kW/°c

Ch = Mh × Cph = 2 kg/s × 4.31 kj/kg °c = 8.62 kW/°c

From the result above cold fluid heat capacity rate is smaller

Dimensionless heat capacity rate, C = minimum capacity/maximum capacity

C= Cmin/Cmax

C = 5.016/8.62 = 0.582

.2 Second, we determine the maximum heat transfer rate, Qmax

Qmax = Cmin (Inlet Temp. of hot fluid - Inlet Temp. of cold fluid)

Qmax = (5.016 kW/°c)(160 - 20) °c

Qmax = (5.016 kW/°c)(140) °c = 702.24 kW

.3 Third, we determine the actual heat transfer rate, Q

Q = Cmin (outlet Temp. of cold fluid - inlet Temp. of cold fluid)

Q = (5.016 kW/°c)(80 - 20) °c

Qmax = (5.016 kW/°c)(60) °c = 303.66 kW

.4 Fourth, we determine Effectiveness of the heat exchanger, ε

ε = Q/Qmax

ε = 303.66 kW/702.24 kW

ε = 0.432

.5 Fifth, using appropriate effective relation for double pipe counter flow to determine NTU for the heat exchanger

NTU = $\\ \frac{1}{C-1} ln(\frac{ε-1}{εc -1} )$

NTU = $\frac{1}{0.582-1} ln(\frac{0.432 -1}{0.432 X 0.582 -1} )$

NTU = 0.661

.6 sixth, we determine Heat Exchanger surface area, As

From the question, the overall heat transfer coefficient U = 640 W/m²

As = $\frac{NTU C{min} }{U}$

As = $\frac{0.661 x 5016 W. °c }{640 W/m²}$

As = 5.18 m²

.7 Finally, we determine the length of the heat exchanger, L

L = $\frac{As}{\pi D}$

L = $\frac{5.18 m² }{\pi (0.015 m)}$

L= 109.91 m

L ≅ 110 m = 11,000 cm

3 0

3 years ago