The nitrogen has been reduced or has undergone reduction and it has gained one electron
<span>PV = nRT
(4000 Torr)(5 L) = n (62.4 Torr-L/mol-K)(296K)
n = 1.08 moles
28 g/mol, 1.08 moles = 30.3 grams
your answer is
C.30.3 g</span>
Answer:
The solubility of the mineral compound X in the water sample is 0.0189 g/mL.
Explanation:
Step 1: Given data
The volume of water sample = 46.0 mL.
The weight of the mineral compound X after evaporation, drying, and washing = 0.87 g.
Step 2: Calculate the solubility of X in water
46.00 mL of water sample contains 0.87 g of the mineral compound X.
To calulate how many grams of the mineral compound 1.0 mL of water sample contains:
0.87 g/46.0 mL = 0.0189 g.
This means the solubility of the mineral compound X in the water sample is 0.0189 g/mL.
Only one molecule have <u>sp2 </u>hybridization on central atom and that is <u>SO₂</u>.
<u>XeCl₂</u> have <u>sp3d </u>hybridization.
<u>OCl₂</u> have <u>sp3 </u>hybridization.
<u>HCN </u>have <u>sp </u>hybridization.
Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.
Hybridization intermixing usually results in the formation of hybrid orbitals having entirely different energies, shapes, etc.
Learn more about hybridization here:- brainly.com/question/22765530
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