Answer:
Explanation:
Hello,
In this case, for the given combustion process, we can compute the present moles of carbon atoms by considering that the only product containing carbon is CO2, thus, we have:
Next, we compute the moles of hydrogen that is present at the water only as a product:
Then, we compute the moles of oxygen by considering the oxygen present in both the CO2 and H2O and the initial sample:
Now, we divide the moles of C, H and O by the moles of O since they are lower amount, in order to compute the subscript in the empirical formula:
But the smallest whole number is:
Regards.
The balanced chemical equation for the standard formation reaction of liquid acetic acid is given as ,
→
The reaction that form the products from their elements in their standard state is called formation of reaction .The acetic acid consist C , H , and O , So, determine their standard state . Carbon is graphite at 25°C and 1 atm , whereas hydrogen and oxygen are diatomic gases . Hence , we start with unbalanced reaction.
→
The balanced chemical equation for the standard formation reaction of liquid acetic acid as,
→
The combustion of liquid acetic acid is given as,
→ ΔH =-873
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Answer:
The answer is:
B
Explanation:
The compound in Option B is Methane.
Methane is known to be a compound which has two elements, carbon and hydrogen. It has a central atom which is surrounded by four hydrogen atoms. It's chemical formula is CH4.
Methane's outer atoms are dipoles and are in the same direction. This makes the overall molecule non-polar. The compound itself has non-polar bonds and it is non-polar itself.