Write a word problem that can be solved by finding the number that have 4 as a factor

Mathematics

1 answer:

Sphinxa [80]3 years ago

5 0

3+1 = 4 , 5- 1 = 4 , 8÷2=4 , 2×2=4

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(3n-2)(4n+1)<br> how do i solve this by factoring?

Anni [7]

Answer:

$12n^2-5n-2$

The expression (3n-2)(4n+1) can be factored with the Distributive Property. It cannot be factored with a Least Common Multiple (LCM), for instance, because the terms within each set of parentheses are completely simplified.

Step-by-step explanation:

Part I

. $1. (3n-2)(4n+1)\\2. F.O.I.L.: 12n^2+3n-8n-2\\3. Simplify: 12n^2-5n-2\\$

Good luck to you!

8 0

2 years ago

Find the sum of 10 + 5i and its complex conjugate.

ra1l [238]

Answer:

20.

Given, complex number is 10+5i .

We need to find sum of the given complex number and its conjugate. The conjugate of 10+5i is 10-5i. Therefore, the sum will be 10+5i+10−5i=20.

3 0

3 years ago

If f(x) = x and g(x) = 2x + 7, what is<br>f[90X)] when g(x) = 11?

kumpel [21]

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