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Sunny_sXe [5.5K]
3 years ago
5

Ann works in a supermarket for $15.00 per hour. If her pay is increased to $18.00, then what is her percent increase in pay?​

Mathematics
2 answers:
wariber [46]3 years ago
4 0

Answer:

previous salary of Ann=$15

Present salary of Ann=$18

The increase in salary=$18-$15

=$3

%increase in salary=increase in salary/previous salary

=($3/$15)×100%

=20%

vfiekz [6]3 years ago
4 0
She would increase 20% of her normal pay
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Pizzas cost $8 and sandwiches cost $2.50
7 0
3 years ago
Shamika's grandmother opens an account with a deposit of $5,000 for Shamika as a college savings account. The account pays 5 per
lesantik [10]

Answer:

$7500

Step-by-step explanation:

$5000 was deposited

5% annual interest of the $5000 is $250

so in ten years the interest will be 10 ×$250 =$2500

so the total sum that will be in the account is $5000 + $2500 =$7500

7 0
3 years ago
I need help with #65 to #70 ASAP please and thank you …. Could someone please help me with it… I need to get it done ASAP… it is
never [62]

All of the given questions(#65 to #70) are AP(s).

Formula to be used: a(n) = a(1) + (n - 1)d

Pronounced as:

nth term = 1st term + (n - 1)d, where d is the common difference.

*d = difference of any two consecutive terms.

65):

1st term = 2, d = 6 - 2 = 4

Therefore,

11th term = 2 + (11 - 1)4 = 42

66):

1st term = 5, d = 15 - 5 = 10

Therefore,

16th term = 5 + (16 - 1)10 = 155

67):

1st term = 19, d = 39 - 19 = 20

Therefore,

21st term = 19 + (21 - 1)20 = 419

68):

1st term = 8, d = 38 - 8 = 30

Therefore,

36th term = 8 + (36 - 1)30 = 1058

69):

1st term = 1/2, d = 1 - 1/2 = 1/2

Therefore,

101st term = 1/2 + (101 - 1)1/2 = 101/2

70):

1st term = 0.75, d = 1.50 - 0.75 = 0.75

Therefore,

151st term = 0.75 + (151 - 1)(0.75) = 113.25

8 0
3 years ago
A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Houston. The stud
iris [78.8K]

Answer:

-0.048

Do not reject  H_0:P_1-P_2=0

Step-by-step explanation:

From the question we are told that

Sample size n_1=350

Sample size n_2=250

Sample proportion 1  \hat P= \frac{25}{350} =>0.07

Sample proportion 2 \hat P= \frac{19}{250} =>0.076

95% confidence interval

Generally for 95% confidence level

Level of significance

 \alpha = 1-0.95=>0.05

 \alpha /2=\frac{0.05}{2} =>0.025

Therefore

Z_a_/_2=1.96

Generally the equation for confidence interval between P_1 - P_2  is mathematically given as

(\hat P_1-\hat P_2)\pm Z_a_/_2\sqrt{\frac{\hat P_1(1-\hat P_1)}{n_1}+\frac{\hat P_2(1-\hat P_2)}{n_2}  }

(0.07-0.076)\pm 1.96\sqrt{\frac{0.07(1-0.07)}{350}+\frac{0.076(1-0.076)}{250}  }

(0.07-0.076)\pm 1.96\sqrt{4.66896*10^-^4  }

(-0.006)\pm 0.042

(-0.006)- 0.042=>-0.048

(-0.006)+ 0.042=>0.036

Therefore

Confidence interval is

-0.048

Conclusion

Given the confidence interval has zero

Therefore do not reject  H_0:P_1-P_2=0

6 0
2 years ago
Explain the equation used to solve for the axis of symmetry.
sertanlavr [38]

Answer:

What the first person said

6 0
3 years ago
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