Number 7 plz!!!! I have no clue and it’s due by midnight!!!!!!!
1 answer:
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Answer:
B) 1st C sp3 ; 2nd C sp3 ; O sp3
Explanation:
Both carbons in ethanol have an sp³ configuration of their orbitals, given that each carbon atom binds to four other atoms, as can be seen on the extended formula in the attachment.
In these carbons (1st and 2nd) one s orbital and three p orbitals are hybridized to form four hybrid orbitals sp³. These orbitals form four bonds and their bond angles are close to the tetrahedral value of 109.5º,as can be seen for methanol which also has an sp³ configuration.
The oxygen atom can also be described as having sp³ hybrid orbitals. Two of the four hybrid sp³ orbitals in oxygen are occupied by lone electron pairs, and two are used to form bonds with other atoms (in this case the oxygen is bonded to a carbon atom and a hydrogen atom).
Therefore, the three central atoms have an sp³ configuration.
Answer:
0.354L
Explanation:
Given parameters:
Molarity of KCN = 0.025M
Number of moles = 8.84 x 10⁻³mol
Unknown:
Volume of KCN = ?
Solution:
The molarity of a substance is expressed as;
Molarity =
Volume of KCN =
Now insert the parameters and solve;
Volume of KCN = = 0.354L