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andrew11 [14]
3 years ago
7

21,980 mg of phosphorus reacts in a gas jar containing oxygen. The resulting oxide weighed 50.000 g. The percent composition of

oxygen in this compound is 43.97%. FALSE or TRUE​
Chemistry
1 answer:
stealth61 [152]3 years ago
8 0

Answer: False

Explanation:

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A car can accelerate from a standstill to 100 km/h [E] in 9.60s. calculate the average acceleration
Lelu [443]

Answer:

Acceleration is :

a = 2.89 m/s2

Explanation:

Acceleration : It is the change in the velocity of the object per unit time.

The object starts from the rest , so the initial velocity of the object is zero.

Initial velocity , u = 0

Final velocity = 100 km/h

Change the velocity to m/s because[ time unit is in second(9.60 s)]

1 km = 1000 m

1 hour = 60 x 60 sec = 3600 sec

1km/h=\frac{1000}{3600}m/s

1km/hr=\frac{5}{18}

100km/hr=\frac{5}{18}\times 100

v=\frac{5}{18}\times 100

v = 27.78 m/s

u = 0 m/s

time = 9.60 s

The acceleration"a" is calculated using :

a=\frac{v-u}{t}

a=\frac{27.78-0}{9.6}

a=\frac{27.78}{9.6}

a=2.89m/s^{2}

5 0
2 years ago
Why is it not possible to directly count the number of particles in a mole?
SVETLANKA909090 [29]

Answer: because a mole is based on Avogrado's number,  which is 6.02 x 10²³ particles. It isn't possible to directly count that many particles at a time.

6 0
3 years ago
How to write a balanced nuclear equation on how uranium can disintegrate to Actium​
andrey2020 [161]

Answer:

Balancing Nuclear Equations

To balance a nuclear equation, the mass number and atomic numbers of all particles on either side of the arrow must be equal.

Explanation:

follows:

6

3

Li

+

2

1

H

→

4

2

He

+

?

To balance the equation above for mass, charge, and mass number, the second nucleus on the right side must have atomic number 2 and mass number 4; it is therefore also helium-4. The complete equation therefore reads:

6

3

Li

+

2

1

H

→

4

2

He

+

4

2

He

Or, more simply:

6

3

Li

+

2

1

H

→

2

4

2

He

image

Lithium-6 plus deuterium gives two helium-4s.: The visual representation of the equation we used as an example.

Compact

5 0
2 years ago
How many formula units make up 24.2 g of magnesium chloride (MgCl2)?<br><br> Help!!
NNADVOKAT [17]

Answer:

Approximately 1.53 \times 10^{23} formula units (0.254\; \rm mol).

Explanation:

Refer to a modern periodic table for the relative atomic mass of magnesium (\rm Mg) and chlorine (\rm Cl):

  • \rm Mg: 24.305.
  • \rm Cl: 35.45.

In other words, the mass of 1\; \rm mol of \rm Mg atoms would be (approximately) 24.305\; \rm g.

Likewise, the mass of 1\; \rm mol of \rm Cl atoms would be approximately 35.45\; \rm g.

One formula unit of the ionic compound \rm MgCl_{2} includes exactly as many atoms as there are in the given formula. The formula mass of a compound is the mass of 1\; \rm mol of the formula units of this compound.

The formula \rm MgCl_{2} includes one \rm Mg atom and two \rm Cl atoms.

Hence, every formula unit of \rm MgCl_{2} \! would include the same number of atoms: one \rm Mg\! atom and two \rm Cl\! atoms. There would be 1\; \rm mol of \rm Mg atoms and 2\; \rm mol of \rm Cl atoms in 1\; \rm mol\! of \rm MgCl_{2} formula units.

Thus, the mass of 1\; \rm mol\! of \rm MgCl_{2} formula units would be equal to the mass of 1\; \rm mol of \rm Mg atoms plus the mass of 2\; \rm mol of \rm Cl atoms. (The mass of 1\; \rm mol\!\! of each atom could be found from the relative atomic mass of each element.)

\begin{aligned}& M({\rm MgCl_{2}}) \\ =\; & 24.305\; {\rm g \cdot mol^{-1}} + 2\times {\rm 35.45 \; \rm g \cdot mol^{-1}} \\ =\; & 95.205\; \rm g \cdot mol^{-1}\end{aligned}.

In other words, the formula mass of \rm MgCl_{2} is 95.205\; \rm g \cdot mol^{-1}.

Therefore, the number of formula units in m = 24.2\; \rm g of \rm MgCl_{2} would be:

\begin{aligned}n &= \frac{m({\rm MgCl_{2}})}{M({\rm MgCl_{2}})} \\ &= \frac{24.2\; \rm g}{95.205\; \rm g\cdot mol^{-1}} \\ & \approx 0.254\; \rm mol\end{aligned}.

Multiple n by Avogadro's Number N_{A} \approx 6.022 \times 10^{23}\; \rm mol^{-1} to estimate the number of formula units in 0.254\; \rm mol:

\begin{aligned}N &= n \cdot N_{A} \\ &\approx 0.254\; \rm mol \times 6.022 \times 10^{23}\; \rm mol^{-1} \\ &\approx 1.53\times 10^{23}\end{aligned}.

6 0
2 years ago
Which of the following describes the bond between nitrogen atoms in an N, molecule? (1) 2 electrons are shared (2) 4 electrons a
uysha [10]

Explanation:

(3) 6 electrons are shared.

7 0
3 years ago
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