The temperature , <u>165 degree F</u> should soup that contains cooked beef be reheated for hot-holding.
Food should reach a temperature serving 135°F before it can be opened in the restaurant and warmed for hot holding. Within two hours, quickly reheat the food. If food is being served right away, it can be served anywhere at temperature as long that it as it was cooked and chilled appropriately.
TCS food must be totally chilled to 41°F or even below in 6 hours after being thoroughly cooled between 135°F to 70°F in 2 hours. Within four hours, TCS food made with ingredients at room temperature needs to be chilled to 41°F or lower.
Therefore, the temperature , <u>165 degree F</u> should soup that contains cooked beef be reheated for hot-holding.
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Pure water is called distilled water or deionized water.
start the balancing by writing down how many atoms there are per element. we’ll use this as an example:
C3H8 + O2 --> H2O + CO2
C = 3 C = 1
H = 8 H = 2
O = 2 O = 3
balance the carbon first, as it is easiest to do. add a coefficient to the single carbon atom on the right of the equation to balance it with the 3 carbon atoms on the left of the equation:
C3H8 + O2 --> H2O + (3)CO2
now there are 3 carbon atoms on each side. however, when you do this, you multiply the amount of oxygen atoms you had. therefore, now, there are 6 carbon atoms in 3CO2, plus that other oxygen atom in H2O. you now have 7 O atoms instead of 3.
C = 3 C = 3
H = 8 H = 2
O = 2 O = 7
now let’s move on to the hydrogen atoms.
C3H8 + O2 --> H2O + 3CO2
you have 8 hydrogen atoms on the left side, and 2 on the right. in order to balance them, you have to multiply the right side’s hydrogen atoms by 4. 4(2) = 8.
C3H8 + O2 --> (4)H2O + 3CO2
now both hydrogen and carbon atoms are balanced. same amount on both sides. however, your oxygen atoms have changed due to the multiplying (right side). you now have 10 of them.
C = 3 C = 3
H = 8 H = 8
O = 2 O = 10
now we balance the oxygen atoms. multiply the left side of the equation’s oxygen atoms by 5. 5(2) = 10
C3H8 + (5)O2 --> 4H2O + 3CO2
the chemical equation is all balanced. basically, just multiply with numbers until it equals the same amount on both sides.
C = 3 C = 3
H = 8 H = 8
O = 10 O = 10
