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kipiarov [429]
3 years ago
8

What is 3.08 x 12.4 ?

Mathematics
1 answer:
lawyer [7]3 years ago
7 0

Answer:

=38.192x

Step-by-step explanation:

I hope this helps you

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What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Ipatiy [6.2K]

Answer:

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

Step-by-step explanation:

2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c =  - 3 \\\\x = \frac{-b^2\  \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

3 0
2 years ago
What is the opposite operation of squaring? Using this opposite operation, rewrite the equation from question 1 so s is by itsel
Radda [10]
The opposite operation of squaring is to find the square root. I dunno what the original equation is so I can’t help with that
5 0
2 years ago
A person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is ce
Scilla [17]
Answer: Assuming the riders starts at the position (20, 0) on the x-axis, the exact position of the rider will be (20cos75, 20sin75) or about (5.18, 19.32).

The angle for 5pi/12 radians is 75 degrees. Therefore, to find the position we can use the sine and cosine of 75 to find the x and y value of the coordinate.

For the y-value, we can write and solve:
sin75 = x/20

For the x-value, we can write and solve:
cos75 = x/20
3 0
3 years ago
Let f(r) = 6,<br> find f-¹(r)
I am Lyosha [343]

There is no answer because there cannot be one to one function inverse.

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1 year ago
How many times can four be subtracted from 2496​
Harrizon [31]

Answer:

624

The drawing will help

4 0
3 years ago
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