Question

A charge Q creates an electric field. A test charge q is usedto measure the strength of the electric field at a distance d from Q. The electric field strength is defined as ____

Answer 1

Answer:

$E=\frac{1}{4\pi.\epsilon_o} \times \frac{Q}{ d^2}$

Explanation:

In the given question we have a test charge q at a distance of d from form another charge Q which creates the field.

The electric field strength is force force per unit test charge, according to the Coulomb's law the force between two charges is given as:

$F=\frac{1}{4\pi.\epsilon_0} \times \frac{Q.q}{d^2}$

where:

$\epsilon_0=$ permittivity of free space

Therefore,

$E=\frac{F}{q}$

$E=\frac{1}{4\pi.\epsilon_o} \times \frac{Q}{ d^2}$