Answer:
Δf = 0.00003 MHz = 30 Hz
Explanation:
The apparent frequency due to the motion of receiver towards the source is given by Doppler's effect, while the source is stationary. Therefore, the formula is given as follows:

where,
f = apparent frequency
c = speed of light = 3 x 10⁸ m/s
v₀ = velocity of observer = 46 m/s
f₀ = Original Frequency = 175 MHz = 175 x 10⁶ Hz
Therefore,

f = 175.00003 MHz
Therefore, the change in frequency is:
Δf = f - f₀
Δf = 175.00003 MHz - 175 MHz
<u>Δf = 0.00003 MHz = 30 Hz</u>
The spring constant is 147 N/m
Given the mass of the block is 2.00 kg , the mass of the body is 300 g and the length of the spring is 2.00 cm
We need to find the spring constant
A spring is an object that can be deformed by a force and then return to its original shape after the force is removed.
The force required to stretch an elastic object such as a metal spring is directly proportional to the extension of the spring
We know that F = kx
300(9.8)= k (0.02)
k = 147.15 N/m
Rounding off to the nearest is 147N/m
The spring constant is 147N/m
Learn more about Hooke's law here
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Answer:
E = 0.01 J
Explanation:
Given that,
The mass of the cart, m = 0.15 kg
The force constant of the spring, k = 3.58 N/m
The amplitude of the oscillations, A = 7.5 cm = 0.075 m
We need to find the total mechanical energy of the system. It can be given by the formula as follows :

Put all the values,

So, the value of total mechanical energy is equal to 0.01 J.
Answer:

Explanation:
Given that,
The work function for silver is 4.73 eV.
We need to find the value of the work function from electron volts to joules.
We know that,

For 4.73 eV,

So, the work function for silver is
.
By Wind
By the Coriolis effect and land
Hope it helped