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KatRina [158]
3 years ago
11

How are kyanite crystals formed

Physics
1 answer:
aev [14]3 years ago
3 0
It occurs as detrital grains in sedimentary rocks. It forms under extreme pressure.
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When 560,000 is written in scientific notation, the power of 10 is
attashe74 [19]
The answer would be 5.6x10^5
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3 years ago
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A wheelchair ramp is 5.2 m long and 0.8 m high. Calculate the ramp’s mechanical advantage
Arlecino [84]

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5

Explanation:

62

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Cuanto cambia la entropía de 0.50 kg de vapor de mercurio [Lv: 2.7 x 10⁵ j/kg ] al calentarse en su punto de ebullición de 357°
lord [1]

Answer:

La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.

Explanation:

Por definición de entropía (S), medida en joules por Kelvin, tenemos la siguiente expresión:

dS = \frac{\delta Q}{T} (1)

Donde:

Q - Ganancia de calor, en joules.

T - Temperatura del sistema, en Kelvin.

Ampliamos (1) por la definición de calor latente:

dS = \frac{L_{v}}{T}\cdot dm (1b)

Donde:

m - Masa del sistema, en kilogramos.

L_{v} - Calor latente de vaporización, en joules

Puesto que no existe cambio en la temperatura durante el proceso de vaporización, transformamos la expresión diferencial en expresión de diferencia, es decir:

\Delta S = \frac{\Delta m \cdot L_{v}}{T}

Como vemos, el cambio de la entropía asociada al cambio de fase del mercurio es directamente proporcional a la masa del sistema. Si tenemos que m = 0.50\,kg,L_{v} = 2.7\times 10^{5}\,\frac{J}{kg} and T = 630.15\,K, entonces el cambio de entropía es:

\Delta S = \frac{(0.50\,kg)\cdot \left(2.7\times 10^{5}\,\frac{J}{kg} \right)}{630.15\,K}

\Delta S = 214.235 \,\frac{J}{K}

La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.

3 0
3 years ago
Can someone plz answere my question<br> for science
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Whats the question?
djdkkd
5 0
3 years ago
Which action best demonstrates the transformation of mechanical energy to heat energy and sound energy?
MrMuchimi

Answer:

striking a hammer on a nail

7 0
4 years ago
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