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mojhsa [17]
4 years ago
5

Ronaldo rolled a number cube 50 times. During these trials he rolled the number 5 a total of 7 times. Based on these trials, wha

t is the probability of rolling a 5? Does this represent a theoretical or experimental probability? Explain.
Mathematics
2 answers:
Goryan [66]4 years ago
6 0
The probability of rolling a 5 is still 1/6, and this is an example of experimental probability. The result of trials not being the same as theoretical results does not change the theoretical probability. The chance of rolling a certain number on a perfect die will always be 1/6.
baherus [9]4 years ago
5 0

Answer:\frac{1}{6}

Step-by-step explanation:

The probability of rolling a 5 is \frac{1}{6} because rolling a die is independent of previous results .It can show any number with equal Probability i.e. \frac{1}{6}

The above case is an example of Experimental probability but the probability is calculated the same way of favorable outcome to the total outcome.

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Answer:3 and 1/8

Step-by-step explanation:by adding

4 0
4 years ago
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The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

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Answer:

the y intercept is 8.54 and the slope would be 0

Step-by-step explanation:

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There are 24 more students in the seventh grade class than the number g in the eighth grade class. The seventh grade class has 1
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Answer:

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