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Zarrin [17]
3 years ago
6

Which physical method can separate a mixture of steel ball bearings and marbles ?

Chemistry
2 answers:
OLEGan [10]3 years ago
8 0

SORTING METHOD can easily be used to separate a mixture of steel ball bearing and marbles. This separation method is suitable because the two substances that are mixed together have big sizes, so it is easy to separate the two by hand picking the particles. Sorting method is usually used as a separation technique when the size of the mixture is big and the mixed substances are in the same state.

Mariana [72]3 years ago
7 0

Answer:

D. Sorting

Explanation:

Just tested

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Why is this image a good model for the Law of Conservation of Mass?
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Answer:

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Explanation:

In the answer.

8 0
3 years ago
2. Suppose that 21.37 mL of NaOH is needed to titrate 10.00 mL of 0.1450 M H2SO4 solution.
AysviL [449]

Answer:

0.1357 M

Explanation:

(a) The balanced reaction is shown below as:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

(b) Moles of H_2SO_4 can be calculated as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For H_2SO_4 :

Molarity = 0.1450 M

Volume = 10.00 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10×10⁻³ L

Thus, moles of H_2SO_4 :

Moles=0.1450 \times {10\times 10^{-3}}\ moles

Moles of H_2SO_4  = 0.00145 moles

From the reaction,

1 mole of H_2SO_4 react with 2 moles of NaOH

0.00145 mole of H_2SO_4 react with 2*0.00145 mole of NaOH

Moles of NaOH = 0.0029 moles

Volume = 21.37 mL = 21.37×10⁻³ L

Molarity = Moles / Volume = 0.0029 /  21.37×10⁻³  M = 0.1357 M

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What is the molar mass of (NH4)2 CO3
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PLEASE TELL ME IF THIS IS RIGHT CLASS IN % MINUTES
alexdok [17]

Answer:

I think that is pretty good and if you get it wrong you showed your work so your teacher can see you're thinking. That is defenetly gonna get you a score.

Explanation:

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3 years ago
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