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Aliun [14]
3 years ago
12

Please help me with the question. Will mark brainliest.

Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0

Step-by-step explanation:

A.) Ok, so the mean price for Southtown is 72,800.

And the mean price for middle town is 54,900

So Southtown has the higher mean price.

Explanation:

To find the mean. You must first add up all the numbers, then divide the total by how many numbers you added up.

72,000 + 50,000 + 68,000 + 93,000 + 81,000 = 364,000

Then,

364,000/ 5 = 72,800

B.) It is 17,900

Explanation:

72,800 - 54,900 = 17,900

Hope this helps you out!!! : )

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2.9 rounded to nearest hundredth
worty [1.4K]

Answer:

The answer would be 2.9

Step-by-step explanation:

its already rounded

8 0
3 years ago
(235) a prime number
Llana [10]

Answer:

235 is not Prime. It’s Composite.

Step-by-step explanation:

Factors of 235:

1, 5, 47, 235.

1 x 235 = 235,

47 x 5 = 235.

Prime Numbers have the number 1 and the number it's self.

This number has 4 factors, which means it’s composite,

Composite Numbers have 3 or more factors.

4 0
3 years ago
Henry was playing checkers with a friend. The ratio of games Henry won was 9 : 4. If Henry won 36 games, how many games did his
patriot [66]
His friend won 16 games
5 0
3 years ago
Read 2 more answers
Luke can buy bottles of water in packages of 6 for $15.24 or in packages of 4 for $11.16. How much money does he save by buying
creativ13 [48]

Answer:

6\ for\ \$15.24\ is\ better\ price\\\\Total\ saving=\$12

Step-by-step explanation:

Cost at the rate 6 for $15.24:

Cost of 6 bottles=\$15.24

Cost of 1 bottle=\$\frac{15.24}{6}

Cost of 48 bottles=\frac{15.24}{6}\times 48=15.24\times 8=\$121.92

Cost at the rate 4 for $11.16:

Cost of 4 bottles=\$11.16

Cost of 1 bottle=\frac{11.16}{4}

Cost of 48 bottles=\frac{11.16}{4}\times 48=11.16\times 12=\$133.92

Hence 6\ bottles\ for\ 15.24 is less expensive.

Total saving=133.92-121.92=\$12

6 0
3 years ago
Compute x/y if
Marysya12 [62]

Let first consider the equations one by one and will be solving one by one ;

{:\implies \quad \sf x+\dfrac{1}{y}=4}

Multiplying both sides by y will lead ;

{:\implies \quad \sf xy+1=4y}

{:\implies \quad \boxed{\sf xy=4y-1\quad \cdots \cdots(i)}}

Now, consider the second equation which is ;

{:\implies \quad \sf y+\dfrac{1}{x}=\dfrac14}

Multiplying both sides by x will yield

{:\implies \quad \sf xy+1=\dfrac{x}{4}}

{:\implies \quad \sf xy=\dfrac{x}{4}-1}

{:\implies \quad \boxed{\sf xy=\dfrac{x-4}{4}\quad \cdots \cdots(ii)}}

As LHS of both equations (i) and (ii) are same, so equating both will yield;

{:\implies \quad \sf 4y-1=\dfrac{x-4}{4}}

Multiplying both sides by 4 will yield

{:\implies \quad \sf 16y-4=x-4}

{:\implies \quad \sf 16y=x}

Dividing both sides by y will yield :

{:\implies \quad \boxed{\bf{\dfrac{x}{y}=16}}}

<em>Hence, the required answer is 16</em>

5 0
2 years ago
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