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Vilka [71]
4 years ago
6

What happens when a star comes to an end?

Physics
2 answers:
nlexa [21]4 years ago
7 0

Answer:

It depends on the size of the star but I think it's B

Explanation:

If the star is massive, it will eventually explode (supernova) and if it is a star with a high mass, the core of it will form a neutron star and if it is very massive the core will turn into a blackhole

Elena-2011 [213]4 years ago
4 0

Answer:

B

Explanation:

It can become a black hole

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5. Work is being done when a force
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work is done when a force is applied. the force must not be zero and should make the object move through a certain distance.

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How much energy must be added to a 2-kg piece of glass with a specific heat
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Answer:

51520J

Explanation:

The energy added to the piece of glass is also called heat needed to increase its temperature from 10°C to 50°C and it depends on the mass, specific heat capacity and the change in temperature.

Q=m.c.ΔT

Q=(2kg).(644J/(kg°C)).((50°C)-(10°C))

Q=51520J                    

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4 years ago
The heat pump is designed to move heat. This is only possible if certain relationships between the heats and temperatures at the
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4 years ago
Noah is loading the ark and the last animal on board is a stubborn 1500-kg elephant who refuses to budge. Noah and his family pu
Oxana [17]

The coefficient of sliding friction is 0.514

Explanation:

We start by writing the equations of motion of the elephant along the two directions, parallel and perpendicular, to the incline.

Along the parallel direction we have:

F- mg sin \theta - \mu_k R = ma (1)

where :

F = 10,000 N is the force applied by Noah

mg sin \theta is the component of the weight parallel to the incline, where:

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

\theta=10^{\circ}  is the angle of incline

\mu_k R is the force of friction, where:

\mu_k is the coefficient of friction

R is the normal reaction  

and a is the acceleration

Perpendicular direction:

R-mg cos \theta =0 (2)

where mg cos \theta is the component of the weight perpendicular to the incline

From (2) we find

R=mg cos \theta

And substituting into (1)

F-mg sin \theta - \mu_k mg cos \theta = ma

We know that the elephant moves at constant speed, so the acceleration is zero:

a = 0

So the equation becomes

F-mg sin \theta - \mu_k mg cos \theta=0

And we can re-arrange it to find the coefficient of friction:

F-mg sin \theta - \mu_k mg cos \theta=0\\\mu_k = \frac{F-m g sin \theta}{mg cos \theta}=\frac{10000-(1500)(9.8)(sin 10)}{(1500)(9.8)(cos 10)}=0.514

Learn more about friction and inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

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