Answer:
0.36 kg-m/s
Explanation:
Given that,
Mass of a ball, m = 0.06 kg
Initial velocity of the ball, u = 20 m/s
Final velocity of the ball, v = 26 m/s
We need to find the change in momentum of the tennis ball. It is equal to the final momentum minus initial momentum
So, the change in momentum of the ball is 0.36 kg-m/s.
Answer:For example, standard atmospheric pressure (or 1 atm) is defined as 101.325 kPa. The millibar, a unit of air pressure often used in meteorology, is equal to 100 Pa. (For comparison, one pound per square inch equals 6.895 kPa.)
Explanation:A pascal is a pressure of one newton per square metre, or, in SI base units, one kilogram per metre per second squared.
I hope this helps.... I'm sorry if it doesn't
The answer is wheel and axle
Answer:
The angular velocity of the propeller is 2.22 rad/s.
Explanation:
The angular velocity (ω) of the propeller is:
Where:
θ: is the angular displacement = 10.6 revolutions
t: is the time = 30 s
Therefore, the angular velocity of the propeller is 2.22 rad/s.
I hope it helps you!
Answer:
Option (D) is correct.
Explanation:
The balloon lands horizontally at a distance of 420 m from a point where it as released.
Velocity of air balloon along +X axis =10 m/s
velocity of ball=4 m/s along + X axis
the velocity of balloon gets added to the velocity of ball. So the resultant velocity of the balloon=10+4 = 14 m/s
time taken= 30 s
The distance traveled is given by d= v t
d= 14 (30)
d= 420 m
Thus the balloon lands horizontally at a distance of 420 m from a point where it as released.
