Answer:
°C = Density of water (g/cm3)
4° = 1.0000
20° = 0.9982
40° = 0.9922
60° = 0.9832
80° = 0.9718
it is C....................
Answer:
(a) Height is 4.47 m
(b) Height is 4.37 m
Solution:
As per the question:
Initial velocity of teh ball, ![v_{o} = 20.0 m/s](https://tex.z-dn.net/?f=v_%7Bo%7D%20%3D%2020.0%20m%2Fs)
Angle made by the ramp, ![\theta = 22.0^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2022.0%5E%7B%5Ccirc%7D)
Distance traveled by the ball on the ramp, d = 5.00 m
Now,
(a) At any point on the projectile before attaining maximum height, the velocity can be given by the eqn-3 of motion:
![v^{2} = v_{o}^{2} - 2gH](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20v_%7Bo%7D%5E%7B2%7D%20-%202gH)
where
H =
g = ![9.8 m/s^{2}](https://tex.z-dn.net/?f=9.8%20m%2Fs%5E%7B2%7D)
![v^{2} = 20^{2} - 2\times 9.8\times 5sin22^{\circ}](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%2020%5E%7B2%7D%20-%202%5Ctimes%209.8%5Ctimes%205sin22%5E%7B%5Ccirc%7D)
= 19.06 m/s
Now, maximum height attained is given by:
![h = \frac{(vsin\theta)^{2}}{2g}](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B%28vsin%5Ctheta%29%5E%7B2%7D%7D%7B2g%7D)
![h = \frac{(19sin(22^{\circ}))^{2}}{2\times 9.8} = 2.60 m](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B%2819sin%2822%5E%7B%5Ccirc%7D%29%29%5E%7B2%7D%7D%7B2%5Ctimes%209.8%7D%20%3D%202.60%20m)
Height from the ground = ![5sin22^{circ} + 2.86 = 1.87 + 2.60 = 4.47m](https://tex.z-dn.net/?f=5sin22%5E%7Bcirc%7D%20%2B%202.86%20%3D%201.87%20%2B%202.60%20%3D%204.47m)
(b) now, considering the coefficient of friction bhetween ramp and the ball,
:
velocity can be given by the eqn-3 of motion:
![v^{2} = v_{o}^{2} - 2gH - \mu gd](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20v_%7Bo%7D%5E%7B2%7D%20-%202gH%20-%20%5Cmu%20gd)
![v^{2} = 20^{2} - 2\times 9.8\times 5sin22^{\circ} - 0.150\times 9.8\times 5](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%2020%5E%7B2%7D%20-%202%5Ctimes%209.8%5Ctimes%205sin22%5E%7B%5Ccirc%7D%20-%200.150%5Ctimes%209.8%5Ctimes%205)
= 18.7 m/s
Now, maximum height attained is given by:
![h = \frac{(vsin\theta)^{2}}{2g}](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B%28vsin%5Ctheta%29%5E%7B2%7D%7D%7B2g%7D)
![h = \frac{(18.7sin(22^{\circ}))^{2}}{2\times 9.8} = 2.50 m](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B%2818.7sin%2822%5E%7B%5Ccirc%7D%29%29%5E%7B2%7D%7D%7B2%5Ctimes%209.8%7D%20%3D%202.50%20m)
Height from the ground = ![5sin22^{circ} + 2.86 = 1.87 + 2.50 = 4.37 m](https://tex.z-dn.net/?f=5sin22%5E%7Bcirc%7D%20%2B%202.86%20%3D%201.87%20%2B%202.50%20%3D%204.37%20m)
In an isometric transformation, the shape does not change size.
<h3>What is
isometric transformation?</h3>
A shape-preserving transformation (movement) in the plane or in space is called an isometric transformation (or isometry). The isometric transformations include translation, rotation, and combinations thereof, such as the glide, which combines a translation with a reflection.
A stiff transformation called an isometry keeps perimeter and area constant while preserving length and angle measurements.
As a result, while dilations are not isometric since the image and preimage are comparable figures rather than congruent figures, translations, reflections, and rotations are.
To know more about isometric transformation refer to: brainly.com/question/110297
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