Calculate the mass of 2.50 mol of methanol.
2 answers:
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11.48-gram of are needed to produce 6.75 Liters of
gas measured at 1.3 atm pressure and 298 K
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 1.3 atm
V= 6.75 Liters
n=?
R=
T=298 K
Putting value in the given equation:
Moles = 0.3588 moles
Now,
Mass= 11.48 gram
Hence, 11.48-gram of are needed to produce 6.75 Liters of
gas measured at 1.3 atm pressure and 298 K
Learn more about the ideal gas here:
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4C₃H₅(NO₃)₃ ------> 12CO₂
+ 6N₂
+ 10H₂O
+ O₂
mol of CO₂ =
=
mol ratio of CO₂ : C₃H₅(NO₃)₃
12 : 4
∴ if mole of CO₂ = 0.568 mol
then " " C₃H₅(NO₃)₃ =
= 0.189 mol
∴ mass of nitroglycerin = mole * Mr
= 0.189 mol * 227.0995 g / mol
= 43.00 g