What is the power of 10 when 75,00 is written in scientific notation

Ganezh [65]

Answer:

protons plus neutrons

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons.

The sum of neutrons and protons is the mass number of an atom.

Mass number = number of protons + number of neutrons

while the number of protons or number of electrons is the atomic number of an atom.

8 0

3 years ago

A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

<u>Explanation:</u>

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

4 0

3 years ago

Acetone, a common solvent, has density 0.79g/cm3 at 20 degrees celcius. What is the volume of 85.1g of acetone at 20 degrees cel

RoseWind [281]

1)

a)

D = 0.79 g/cm³ m = 85.1 g

D = m / V

0.79 = 85.1 / V

V = 85.1 / 0.79 => 107.72 cm³
____________________________________________
b) D = m / V

0.79 = m / 125

m = 0.79 x 125 => 98.75 g
____________________________________________

hope this helps!

4 0

3 years ago

Read 2 more answers

What takes place during a redox reaction

VladimirAG [237]

Electrons are both gained and lost.

7 0

3 years ago

Read 2 more answers

What is the democritus findings?

Volgvan

nvm

4 0

3 years ago