Explanation:
To out this fraction in its simplest form, you need to multiply the 8 by the 1 and then add the 1 in the numerator.
You end up getting

Answer:

Answer:
In your science class, you will learn about Newton’s laws of motion. Do you know why these laws are so important? When you throw a baseball or you bounce a basketball on the court, you can use Newton’s laws to explain the motion of the baseball or basketball. In fact, almost all motion in the world can be explained by these laws. Newton’s laws are useful when people design airplanes, trains, cars, sports equipment, toys, and many things that have to do with motion. Some people have trouble understanding Newton’s laws of motion because it’s hard to see how the laws work without any examples. One great way to understand these laws is to look at how they relate to cars in everyday life.
The First Law of Motion
“Every object persists in its state of rest or uniform motion in a straight line unless it is compelled to change that state by forces impressed upon it.”
Can you see why it’s hard for some people to understand the first law? Those are some complicated words. To help you to understand better, let’s break it down and use the example of a car. The first part deals with an object in a “state of rest”. This means that the object is not moving. When your mom or dad parks the car in the garage or the shopping mall, the car is said to be in a “state of rest” because it is not moving. The car will not move until the engine is started and somebody drives it away. The second part deals with an object in “uniform motion”. This means that the object is moving at the same speed. When you mom or dad is using “cruise control” on a highway at 60 miles per hour, the car will be moving at that speed in a “straight line” until something happens to change it. What is this change? It depends. By using the brakes, your mom or dad can slow the car down or bring it to a stop. On the other hand, the car’s direction will be changed if it is hit by another motor vehicle.Explanation:
There are three major steps for finding an empirical formula from a combustion reaction.
1.) Determine the grams of carbon and hydrogen from the given data.
C: 23.98 g x (12.011 g / 44.01 g) = 6.54 g C
H: 4.91 g x (2.0158 g / 18.02 g) = 0.55 g H
Determine the grams of oxygen in the sample by subtracting the mass of the compound given from the total mass solved earlier.
O: 10.0 - (6.54 + 0.55) = 2.91 g O
2) Convert the values in step 1 to moles.
C: 6.54 g / 12.01 g / mol = 0.54 mol
H: 0.55 g / 1.01 g/mol = 0.54 mol
O: 2.91 g / 16.00 g/mol = 0.18 mol
3) Divide each by the lowest value calculated in step 2
C: 0.54 mol / 0.18 mol = 3
H: 0.54 mol / 0.18 mol = 3
O: 0.18 mol / 0.18 mol = 1
Thus, the empirical formula is C3H3O.
A satellite. The Moon of Earth is a satellite, the over 60 moons Jupiter are all satellites.
ans is carbondioxide and water