The mass percentage of hydrogen in 300 g of sucrose is 9.75%
From the question given above, we were told that:
2 g of sucrose contains 6.50% (ie 0.065) hydrogen
Thus, we can obtain the percentage of hydrogen in 300 g of sucrose as follow:
2 g of sucrose contains 0.065 hydrogen.
Therefore,
300 g of sucrose will contain = = 9.75% of Hydrogen.
Thus, 300 g of sucrose contain 9.75% of Hydrogen.
Learn more: brainly.com/question/16559402
Answer:
-776 KJ/mol
Explanation:
We must look towards the balanced reaction equation in order to obtain the number of electrons transferred in the redox reaction.
3Cu(s) + 2MnO4^-(aq) + 8H^+(aq)------>3Cu2+(aq) + 2MnO2(s) + 4H2O(l)
We can easily see that copper lost six electrons while Manganese gained six electrons hence n=6
ΔG =-nFEcell
Where;
n= 6
F = 96500 C
Ecell=+1.34
ΔG = -(6 * 96500 * 1.34)
ΔG = -776 KJ/mol
Answer:
This solution is called a buffer.
Explanation
It is an aqueous solution containing a weak acid and its conjugate base or a weak base and its conjugate acid. A buffer's pH changes very little when a small amount of strong acid or base is added to it. It is used to prevent any change in the pH of a solution, regardless of solute..
<u>Hope it helps u</u>
<em>Pls mark as brainliest..</em>
Answer:
1 grams Hydrogen is equal to 0.992122546977 mole.
Explanation:
so 0.992122546977 X 22 = 21.8266960335
<span>Ag++Clâ’→AgCl(s)âŹâ†“
We need to add over 1 g KCl.
Moles of silver in solution = 1.77â‹…g107.87â‹…gâ‹…molâ’1` = 0.0164â‹…mol
Clearly we need an equivalent quantity of chloride, thus we add a mass of potassium chloride = 0.0164â‹…molĂ—74.55â‹…gâ‹…molâ’1 = ??â‹…g
The 1 equiv will precipitate most of the silver ion. Silver chloride will possess some aqueous solubility. The result is a curdy white precipitate of silver chloride.</span>