Answer:
4.59 × 10⁻³⁶ kJ/photon
Explanation:
Step 1: Given and required data
- Wavelength of the violet light (λ): 433 nm
- Planck's constant (h): 6.63 × 10⁻³⁴ J.s
- Speed of light (c): 3.00 × 10⁸ m/s
Step 2: Convert "λ" to meters
We will use the conversion factor 1 m = 10⁹ nm.
433 nm × 1 m/10⁹ nm = 4.33 × 10⁷ m
Step 3: Calculate the energy (E) of the photon
We will use the Planck-Einstein's relation.
E = h × c/λ
E = 6.63 × 10⁻³⁴ J.s × (3.00 × 10⁸ m/s)/4.33 × 10⁷ m
E = 4.59 × 10⁻³³ J = 4.59 × 10⁻³⁶ kJ
KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol
HNO3= 1 mol KOH (keep in mind this because it will be used later).
We also know that 0.100 M KOH aqueous
solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the
definition of molarity).
First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/
1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.
Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.
The final answer is </span>(2) 20.0 mL.<span>
Also, this problem can also be done by using
dimensional analysis.
Hope this would help~
</span>
Answer:

Explanation:
The number of valence electrons tells us the group number of the neutral atom.
The atom has 4 valence electrons.
The atom is in group 4.
Answer : The non-bonding and bonding electrons are 10 and 14 respectively.
Explanation :
Electron-dot structure : It is also known as Lewis-dot structure. It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
The given molecule is, Acetyl chloride 
Carbon has '4' valence electrons, hydrogen has '1' valence electron, oxygen has '6' valence electrons and chlorine has '7' valence electrons.
Therefore, the total number of valence electrons in
= 2(4) +3(1) +6 +7 = 24
According to electron-dot structure, there are 14 number of bonding electrons ans 10 number of non-bonding electrons.
The electron-dot structure of
is shown below.
Answer:
d. Transketolase
Explanation:
Transketolase utilize thiamine diphosphate (ThDP) as cofactor has reduced activity during the thiamine deficiency and results in the tissue damage. <u>The levels of steady-state mRNA of transketolase in human lymphoblasts, fibroblasts and neuroblastoma cells are found to be lower in the thiamine-deficient cultures. </u>
Thus, deficiency in TPP directly decrease the activity of enzyme, transketolase.