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Feliz [49]
3 years ago
6

A student is asked to determine the molarity of a strong base by titrating it with 0.250 M solution of H2SO4. The students is in

structed to pipet a 20.0 mL portion of the strong base solution into a conical flask, to add two drops of an indicator that changes at pH = 7, and to dispense the standard H2SO4 solution from a buret until the solution undergoes a permanent color change. The initial buret reading is 5.00 mL and the final reading is 30.00 mL at the equivalence point.Which procedural error will result in a strong base molarity that is too high?Using an indicator that changes at pH = 5 rather than at pH = 7Using a buret with a tip filled with air rather than the H2SO4 solutionUsing 4 drops of indicator rather than the recommended 2 dropsUsing a conical flask that contains several drops of H2O
Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

i working on this too

i might be able to tell u the right answer when im done

Explanation:

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A galvanic (voltaic) cell consists of an electrode composed of nickel in a 1.0 M nickel(II) ion solution and another electrode c
Andre45 [30]

<u>Answer:</u> The standard potential of the cell is 0.77 V

<u>Explanation:</u>

We know that:

E^o_{Ni^{2+}/Ni}=-0.25V\\E^o_{Cu^{+}/Cu}=0.52V

The substance having highest positive E^o reduction potential will always get reduced and will undergo reduction reaction.

The half reaction follows:

<u>Oxidation half reaction:</u> Ni(s)\rightarrow Ni^{2+}(aq)+2e^-

<u>Reduction half reaction:</u> Cu^{+}(aq)+e^-\rightarrow Cu(s)       ( × 2)

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation follows:

E^o_{cell}=0.52-(-0.25)=0.77V

Hence, the standard potential of the cell is 0.77 V

5 0
3 years ago
Where is enery convert to a more usabled form in a process called cellular respiration?
kari74 [83]
Adenosine triphosphate is the correct answer
7 0
4 years ago
Draw the product of the hydrogenation of cis-2-pentene. draw all hydrogen atoms. g
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Hope the diagram below will help you. when a C=C is hydrogenated it gains 2 hydrogens turning it into a C-C.

Hope that helps 

5 0
3 years ago
Read 2 more answers
How do you know whether to use a lone pair or a double bond when drawing a Lewis dot structure?
Charra [1.4K]
Well that depends on the central atom. Remember each bond indicates another electron that is being shared with the central atom.
So CO4, carbon would be your central atom, with the 4 oxygen around it. There would be no double bonds because carbon only requires the 4 electrons provided by the oxygens, because of its location on the periodic table.
Nitrogen on the other hand is different. It's found in group 5 (5V) and has 5 valence electrons on its outer shell. So NO4 would have a central Nitrogen atom, with 3 oxygens providing a single bond, and one oxygen providing a double bond, because Nitrogen needs 5 electrons!
We learned it like this, the atom brought x amount of electrons to the party, x representing the valence electrons, and must leave with x electrons. It's silly but it works!
I hope I was able to help and clarify a few things up!
6 0
3 years ago
Air trapped in a cylinder fitted with a piston occupies 145.7 mL at 1.08 atm pressure. What is the new volume when the piston is
Anon25 [30]

The new volume of air trapper in the cylinder is determined as 116.56 mL.

<h3>New volume of air in the cylinder</h3>

The volume of air trapper in the cylinder is determined from Boyle's law;

P₁V₁ = P₂V₂

where;

  • P₁ is initial pressure = 1.08 atm
  • V₁ is initial volume = 145.7 mL
  • P₂ is new pressure = 1.25 x 1.08 atm = 1.35 atm
  • V₂ is new volume = ?

V₂ = (P₁V₁)/P₂

V₂ = (1.08 x 145.7)/1.35

V₂ = 116.56 mL

Thus, the new volume of air trapper in the cylinder is determined as 116.56 mL.

Learn more about volume here: brainly.com/question/1972490

#SPJ1

6 0
2 years ago
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