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Feliz [49]
3 years ago
6

A student is asked to determine the molarity of a strong base by titrating it with 0.250 M solution of H2SO4. The students is in

structed to pipet a 20.0 mL portion of the strong base solution into a conical flask, to add two drops of an indicator that changes at pH = 7, and to dispense the standard H2SO4 solution from a buret until the solution undergoes a permanent color change. The initial buret reading is 5.00 mL and the final reading is 30.00 mL at the equivalence point.Which procedural error will result in a strong base molarity that is too high?Using an indicator that changes at pH = 5 rather than at pH = 7Using a buret with a tip filled with air rather than the H2SO4 solutionUsing 4 drops of indicator rather than the recommended 2 dropsUsing a conical flask that contains several drops of H2O
Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

i working on this too

i might be able to tell u the right answer when im done

Explanation:

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PLEASE ITS DUEE TODAY at 6:00PM!!!!!
nata0808 [166]

Answer:

I got you... 2 amino acids are linked to each other by a peptide linkage. A peptide linkage is formed when carboxyl group of one amino acid combine with the amine group of the other and during this process, a water molecule is removed.  

The given tripeptide will have 2 peptide bonds. To draw the structure of given tripeptide, we will arrange them in the given order and then we will remove 2 water molecules to form 2 peptide bonds.

 

Explanation:

Hope this helps:)

6 0
2 years ago
Write the Noble Gas Notation for Silicone
ozzi

Answer:

[Ne] 3s2 3p2

Explanation:

Neon (Ne) is the noble gas right before silicon (Si).

Then right after neon is the 3s subshell. It has two electrons and is full.

After 3s comes the 3p subshell, and silicon only has two electrons in the 3p subshell (you can just count the electrons in each subshell on your periodic table).

8 0
3 years ago
How many molecules of H2O are equivalent to 98.2 g of H2O
GREYUIT [131]

Answer:

Demo Mole Quantities

58.5g NaCl(mol/58.5g)(6.02 x 1023/mol) = 6.02 x 1023 Na

+

Cl21 pre-1982 pennies (after 1982 pennies are mostly zinc with copper coating)

63.5g Cu( mol/ 63.5g)(6.02 x 1023/mol) = 6.02 x 1023 Cu

19.0g Al (mol/27.0g)(6.02 x 1023/mol) = 4.24 x 1023 Al

Explanation:

3 0
3 years ago
Using this equation, m1v2=m2v2 , calculate the diluted molarity of 100 mL of a 0.5 M solution when 50 mL of
geniusboy [140]

The molarity of the diluted solution is 0.33 M

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 0. 5 M

Volume of stock solution (V₁) = 100 mL

Volume of diluted solution (V₂) = 100 + 50 = 150 mL

<h3>Molarity of diluted solution (M₂) =? </h3>

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

<h3>M₁V₁ = M₂V₂</h3>

0.5 × 100 = M₂ × 150

50 = M₂ × 150

Divide both side by 150

M₂ = 50 / 150

<h3>M₂ = 0.33 M</h3>

Therefore, the molarity of the diluted solution is 0.33 M

Learn more: brainly.com/question/24625656

8 0
3 years ago
A student weighs out a 2.23 g sample of KF, transfers it to a 300 ml volumetric flask, adds enough water to dissolve it and then
densk [106]
Answer: i d8nt kn09.
7 0
3 years ago
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