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Feliz [49]
3 years ago
6

A student is asked to determine the molarity of a strong base by titrating it with 0.250 M solution of H2SO4. The students is in

structed to pipet a 20.0 mL portion of the strong base solution into a conical flask, to add two drops of an indicator that changes at pH = 7, and to dispense the standard H2SO4 solution from a buret until the solution undergoes a permanent color change. The initial buret reading is 5.00 mL and the final reading is 30.00 mL at the equivalence point.Which procedural error will result in a strong base molarity that is too high?Using an indicator that changes at pH = 5 rather than at pH = 7Using a buret with a tip filled with air rather than the H2SO4 solutionUsing 4 drops of indicator rather than the recommended 2 dropsUsing a conical flask that contains several drops of H2O
Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

i working on this too

i might be able to tell u the right answer when im done

Explanation:

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Jean and her mother were taking a walk when they saw the two rocky outcrops in the diagram below.
Veseljchak [2.6K]

Answer:

you have to attach the diagram

Explanation:

5 0
2 years ago
The average temperature of healthy person is 98.6°F. What is it in<br> Celsius scale?
meriva

Answer:

37 Degrees Celsius

Explanation:

3 0
1 year ago
What’s different about ionic bonding and covalent bonding ? (Help I need the answer ASAP)
Artemon [7]
The two main types of chemical bonds are ionic and covalent bonds. An ionic bond essentially donates an electron to the other atom participating in the bond, while electrons in a covalent bond are shared equally between the atoms. The only pure covalent bonds occur between identical atoms.
3 0
3 years ago
if 5430 J of energy is used to heat 1.25 L of room temp. water (23.0 °C) whats the final temp of the water?
skelet666 [1.2K]

<span>We can use the heat equation,
Q = mcΔT </span>

 

<span>Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>


Density = mass / volume


The density of water = 0.997 g/mL

<span>Hence mass of 1.25 L (1250 mL) of water = 0.997 g/mL x 1250 mL</span>

<span>                                                                   = 1246.25 g</span>


Specific heat capacity of water = 4.186 J<span>/ g °C.</span>


Let's assume that there is no heat loss to the surrounding and the final temperature is T.

By applying the equation,

      5430 J = 1246.25 g x 4.186 J/ g °C x (T - 23) °C
(T - 23) °C = 5430 J / 1246.25 g x 4.186 J/ g °C
(T - 23) °C = 1.04 °C
               T = 1.04 °C + 23 °C
               T = 24.04 °C

Hence, the final temperature of the water is 24.04 °C.
4 0
3 years ago
The volume of a sample of gas at 273 K is 200. liters. If the volume is doubled at constant pressure, what will be the new tempe
gayaneshka [121]

Answer:

New temperature = 546 K

Explanation:

Given that,

Initial volume, V = 200 L

Initial temperature, T = 273 K

We need to find the new temperature if the volume is doubled.

The relation between temperature and volume is direction. If volume is doubled, it means the temperature gets also doubled.

New temperature of the gas = 2(273) = 546 K

8 0
3 years ago
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