<h2>Natural Abundance for 10B is 19.60%</h2>
Explanation:
- The natural isotopic abundance of 10B is 19.60%.
- The natural isotopic abundance of 11B is 80.40%.
- The isotopic masses of boron are 10.0129 u and 11.009 u respectively.
For calculation of abundance of both the isotopes -
Supposing it was 50/50, the average mass would be 10.5, so to increase the mass we need a more percentage of 11.
Determining it as an equation -
10x + 11y= 10.8
x+y=1 (ratio)
10x + 10y = 10
By taking the denominator away from the numerator
we get;
y = 0.8
x + y = 1
∴ x = 0.2
To get percentages we need to multiply it by 100
So, the calculated abundance is 80% for 11 B and 20% 10 B.
Answer:
The value is 
Explanation:
From the question we are told that
The initial volume of the fluorocarbon gas is 
The final volume of the fluorocarbon gas is
The initial temperature of the fluorocarbon gas is 
The final temperature of the fluorocarbon gas is 
The initial pressure is 
The final pressure is 
Generally the equation for adiabatically reversible expansion is mathematically represented as
![T_2 = T_1 * [ \frac{V_1}{V_2} ]^{\frac{R}{C_v} }](https://tex.z-dn.net/?f=T_2%20%3D%20%20T_1%20%20%2A%20%5B%20%5Cfrac%7BV_1%7D%7BV_2%7D%20%5D%5E%7B%5Cfrac%7BR%7D%7BC_v%7D%20%7D)
Here R is the ideal gas constant with the value
So
![248.44 = 298.15 * [ \frac{V}{2V} ]^{\frac{8.314}{C_v} }](https://tex.z-dn.net/?f=248.44%20%3D%20%20%20298.15%20%20%2A%20%5B%20%5Cfrac%7BV%7D%7B2V%7D%20%5D%5E%7B%5Cfrac%7B8.314%7D%7BC_v%7D%20%7D)
=> 
Generally adiabatic reversible expansion can also be mathematically expressed as
=>![[ 81.840 *10^3] [2V]^{\gamma} = [202.94 *10^3] V^{\gamma}](https://tex.z-dn.net/?f=%20%5B%2081.840%20%2A10%5E3%5D%20%5B2V%5D%5E%7B%5Cgamma%7D%20%3D%20%5B202.94%20%2A10%5E3%5D%20V%5E%7B%5Cgamma%7D)
=> 
=> 
So
=>
Answer:
P₅O₁₂
<em>Explanation: </em>
Assume that you have 100 g of the compound.
Then you have 44.7 g P and 55.3 g O.
1. Calculate the <em>moles</em> of each atom
Moles of P = 44.7 × 1/30.97 = 1.443 mol Al
Moles of O = 55.3 × 1/16.00 = 3.456 mol O
2. Calculate the <em>molar ratios</em>.
P: 1.443/1.443 = 1
O: 3.456/1.443 = 2.395
3. Multiply by a number to make the ratio close to an integer
P: 5 × 1 = 5
O: 5 × 2.395 = 11.97
3. Determine the <em>empirical formula
</em>
Round off all numbers to the closest integer.
P: 5
O: 12
The empirical formula is <em>P₅O₁₂</em>.
I think the correct answer is B. J.J. Thompson's Plum Pudding model had to be revised because atoms have protons and neutrons in the nucleus. He realized that aside from the electrons which are negatively charged, positive charge particles should be present to neutralize the charge of an atom.
