Answer:
(a) CH3CH2CH2CH2CH3(l)
(b) CH3CH2OH(l)
- Dipole-dipole interaction
- Dispersion forces
- Hydrogen bonding
(c) H2CO(l)
(d) O2(l)
Explanation:
Dispersion forces are those forces that occur between two non polar molecules.They form the weakest bonds.Here electrons of one molecule is attracted to the nucleus of the other molecule. Example are;
- Interaction of two methyl (-CH₃) group
- Interaction between nitrogen gas , N₂ molecules
- Interaction between oxygen gas ,O₂ molecules
Dipole-Dipole interaction happens when two polar molecules interact.Positive charges in one molecule is attracted to negative charge of another molecule.Examples
- Chloroform (CHCl₃)
- Ammonia (NH₃)
Hydrogen bonding are created when an hydrogen atom bonded to an electronegative atom is attracted to a another electronegative atom.Example is the hydrogen bond between oxygen atom and hydrogen is water (H₂O).
Answer:
2-methyl-2-pentyl-1,3-dioxolane
Explanation:
In this case, we have two reactions:
First reaction:
1-heptyne + mercuric acetate -------> Compound A
Second reaction:
Compound A + HOCH2CH2OH -------> Compound C
<u>First reaction</u>
In the first reaction, we have as a main functional group a triple bond. We have to remember that mercuric acetate in sulfuric acid will produce a ketone. The carbonyl group (C=O) would be placed in the most substituted carbon of the triplet bond (in this case, carbon 2). With this in mind, we will have as a product: heptan-2-one. (See figure 1).
<u>Second reaction</u>
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In this reaction, we have as reagents:
-) Heptan-2-one
-) Ethylene-glycol 
-) Sulfuric acid 
When we put ethylene-glycol with a ketone or an aldehyde we will form a cyclic acetal. In this case, this structure would be formed on carbon 2 forming 2-methyl-2-pentyl-1,3-dioxolane. (See figure 2).
I hope it helps!
Answer:
–2733.4 KJ
Explanation:
The balanced equation for the reaction is given below:
C₂H₅OH + 3O₂ —> 2CO₂ + 3H₂O
ΔH = −1366.7 kJ
From the balanced equation above,
1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.
Finally, we shall determine the enthalpy change (ΔH) produced by the reaction of 2 moles of C₂H₅OH. This can be obtained as follow:
From the balanced equation above,
1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.
Therefore, 2 moles of C₂H₅OH will react to produce enthalpy change (ΔH) of = 2 × −1366.7 = –2733.4 KJ.
Thus, enthalpy change (ΔH) obtained is –2733.4 KJ
It's B Covalent.Now I'll add more words since the thing says I need to write at least 20 characters.
A catalyst is a substance added to the reaction that lowers the activation energy by providing an alternate pathway for the reactions to go to completion.
A catalyst is a substance that accelerates a chemical response, or lowers the temperature or strain needed to begin one, with out itself being ate up at some stage in the response. Catalysis is the procedure of adding a catalyst to facilitate a response.
Catalysts may be categorized as homogeneous, heterogeneous, or enzymatic. Homogeneous catalysts exist inside the identical phase as the reactants, whereas heterogeneous catalysts exist in a exclusive section than the reactants.
Catalysts are basically categorised into 4 kinds.Homogeneous, Heterogeneous, Heterogenized homogeneous catalyst and Biocatalysts. Homogeneous catalyst: In homogeneous catalysis, reaction mixture and catalyst both are gift inside the equal segment.
Learn more about catalyst here:-brainly.com/question/12507566
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