Answer:
0.104 M
Explanation:
<em>A saline solution contains 0.770 g of NaCl (molar mass = 58.55 g/mol) in 133 mL.</em>
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The molar mass of the solute (NaCl) is 58.55 g/mol. The moles corresponding to 0.770 g are:
0.770 g × (1 mol/55.85 g) = 0.0138 mol
The volume of solution is 133 mL. In liters,
133 mL × (1 L/1000 mL) = 0.133 L
The molarity of NaCl is:
M = moles of solute / liters of solution
M = 0.0138 mol / 0.133 L
M = 0.104 M
<span>The concentration of iodide ions doubled.
<span>From what was found in part a, the reaction rate increases by a factor of about 4.</span></span>
Question 9. The first one is the smallest. Anything with a negative exponent is going to be less than 1, the .00000241. The exponent tells you the number of zeroes to the right of the decimal point. Farther to right gets smaller and smaller.
Question 10. The last one is true. If the last digit is smaller than 5, drop the digit, and do not change. (If it is a 5 or larger, the digit before it would round up)
If the object is less dense then the object will float
<span>Molecules condense when the temperature decreases :)</span>