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il63 [147K]
3 years ago
13

HELP ASAP!! DUE NOW!! WILL MARK AS BRAINLIEST IF ANSWERED WITHIN 5-10 MINUTES

Chemistry
1 answer:
AlladinOne [14]3 years ago
6 0
1. NaCl
2. CaO
3. KOH
4. MgS
5. CuCO3
6. Al2O3
7. Fe2O3
8. Na2CO3
9. AlHO3
10. (NH4)3N
11. Zn3N2
12. MgCO3

All numbers are subscripts.
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23492u undergoes alpha decay. what is the atomic number of the resulting element.
mash [69]
Alpha decay involves the loss of an alpha particle, aka a helium nucleus. This results in the mass number of the original element decreasing by 4 and the atomic number decreasing by 2. Assuming 23942u is uranium (92), the resulting element's atomic number is 90, making it thorium.
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A 24.81g sample of a gaseous compound containing only oxygen,and chlorine is determined to contain 3.01g carbon, 4.00g oxygen an
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Answer:

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Explanation:

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3 years ago
What is the formula for the compound dinitrogen pentoxide? n4o5 n5o4 n4o6 n5o2 n2o5?
STALIN [3.7K]
<span>N2, penta means 5, so 5 oxygens

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5 0
3 years ago
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A piece of metal with a mass of 114 g was placed into a graduated cylinder that contained 25. 00 ml of water, raising the water
alexgriva [62]

The density of the metal is 6.51 g/cm3 .

<h3>What is density, for instance?</h3>

How much "stuff" is contained in a specific quantity of space is determined by its density. For instance, a block of the harder, lighter material gold (Au) will be denser than a block of the heaviest element lead (Pb) (Au). Styrofoam blocks are less dense than bricks. Mass per unit size serves as its definition.

Briefing :

mass, m = 114 g

initial volume, V1 = 25 mL

final volume, V2 = 42.5 mL

Volume of the metal piece, V = V2 - V1

                                                 = 42.5 - 25

                                                 = 17.5 mL

1 mL = 1 c.c

So, Volume of metal, V = 17.5 c.c.

Let the density of the metal is d.

density = mass / volume

         d = 114 / 17.5

            = 6.51 g/c.c

Thus, the density of metal is 6.51 g/c.c.

To know more about density visit ;

brainly.com/question/15164682

#SPJ4

3 0
1 year ago
What volume in L of a 0.724 M Nal solution contains 0.405 mol of Nal?
Setler [38]

Answer:

0.559 L

Explanation:

Step 1: Given data

  • Moles of sodium iodide (n): 0.405 mol
  • Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)

Step 2: Calculate the volume of solution (V)

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

V = n/M

V = 0.405 mol/(0.724 mol/L) = 0.559 L

4 0
2 years ago
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