Answer:
80 MOLES OF WATER ARE PRODUCED WHEN 20 MOLES OF PROPANE ARE BURNED IN EXCESS OXYGEN ON A GAS GRILL.
Explanation:
Equation for the reaction:
C3H8 + 5 O2 ---------> 4 H2O + 3 CO2 + Heat
The above equation is in the presence of excess oxygen.
In this reaction,
1 mole of propane forms 4 moles of H2O
If 20 moles of propane were to be used, how many moles of water will be produced?
1 mole of propane = 4 moles of water
20 moles of propane = ( 4 * 20 ) moles of water
= 80 moles of water.
So, if 20 moles of propane were burned in excess oxygen, 80 moles of water will be formed. Propane is heavier than air and when properly combusted produces a large amount of heat. It is also non toxic.
Answer:
Four (4) hydrogen atoms
Explanation:
C=C-C(triple bond)C
only four hydrogen atoms can bond with the vacant space
To determine the amount of 6.0 M H2SO4 needed for the preparation, equate the number of moles of the 6.0 M and 2.5 M H2SO4 solution. This is done as follows
M1 x V1 = M2 x V2
Substituting the known variables,
(6.0 M) x V1 = (2.5 M) x (4.8 L)
Solving for V1 gives an answer of V1 = 2 L. Thus, to prepare the needed solution, dilute 2 L of 6.0 M H2SO4 solution with water until the volume reach 4.8 L.
