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Monica [59]
3 years ago
12

What's that mean phantom?

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
4 0
Here is the definition of phantom:

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Balancing Equations. How many of the element should I drag to the center?
babunello [35]

Answer:

4FeS + 7O₂ ----> 2Fe₂O₃ + 4SO₂

Explanation:

You have to drag the elements shown on the right under the formula.  For example, you would have to drag 4 of the FeS molecules under the 4FeS text in the formula.  Then place 7 O₂ molecules under the 7O₂ text, etc.

8 0
2 years ago
A 0.15 m aqueous solution of a weak acid has a freezing point of -0.31 °C. What is the percent ionization of this weak acid at t
tensa zangetsu [6.8K]

Answer:

11%

Explanation:

1) Calculate van 't Hoff factor:

Δt = i Kf m

0.31 = i (1.86) (0.15)

i = 1.111

2) Calculate value for [H+]:

CCl3COOH ⇌ H+ + CCl3COO¯

total concentration of all ions in solution equals:

(1.11) (0.15) = 0.1665 m

This is a molality, but we will act as if it a molarity since we will assume the density of the solution is 1.00 g/cm3, which makes the molarity equal to the molality.

0.1665 = (0.15 − x) + x + x

x = 0.0165 M

3) Calculate the percent dissociation:

0.0165/ 0.15 = 11 %

4 0
3 years ago
Which arrow in the diagram represents the burning of fossil fuels? Choose 1 answer: Choose 1 answer: (Choice A) A arrow 1 (Choic
Alona [7]

Answer: arrow 4

Explanation:

7 0
2 years ago
In an acid-base neutralization reaction 38.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution.
DaniilM [7]

Answer:

0.2 M.

Explanation:

  • For the acid-base neutralization, we have the role:

The no. of millimoles of acid is equal to that of the base at the neutralization.

<em>∴ (XMV) KOH = (XMV) H₂SO₄.</em>

X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),

M is the molarity.

V is the volume.

  • For KOH:

X = 1, M = 0.5 M, V = 38.74 mL.

  • For H₂SO₄:

X = 2, M = ??? M, V = 50.0 mL.

∴ M of H₂SO₄ = (XMV) KOH/(XV) H₂SO₄ = (1)(0.5 M)(38.74 mL)/(2)(50.0 mL) = 0.1937 M ≅ 0.2 M.

5 0
3 years ago
Classify the reaction by their type. Note there may be more than one way to classify a reaction.
Nadya [2.5K]

Answer:

Redox reaction and single displacement

Explanation:

This reaction is first of all a redox reaction. A redox reaction is a reaction that involves both oxidation and reduction. Oxidation involves increase in oxidation number while reduction involves decrease in oxidation number.

Copper (Cu) had an oxidation number of "0" as a reactant but had an oxidation number of "2+" in the product [Cu(NO₃)₂] hence oxidation occurred.

Nitrogen (N) had an oxidation number of "5+" in the reactant (HNO₃) but had an oxidation number of "4+" in the product (NO₂) hence reduction also occurred.

Also, from the reaction, it can be deduced that copper (Cu) displaced hydrogen (H) from the nitric acid (HNO₃) solution to form copper (II) nitrate [Cu(NO₃)₂]. It should be noted that copper can displace hydrogen because it is higher than hydrogen in the electrochemical series. Hence, this reaction can also be called a single displacement reaction. A single displacement reaction is a reaction in which an atom of an element replaces another atom in a compound (as seen in the equation given in the question).

3 0
3 years ago
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