A Url An Wireless Router And A Cable Line And A Wifi Box (In The Wall) And Ethernet Cables
Answer:
Explanation:
One group of students did an experiment to study the movement of ocean water. The steps of the experiment are listed below.
Fill a rectangular baking glass dish with water.
Place a plastic bag with ice in the water near the left edge of the dish.
Place a lighted lamp near the left edge of the dish so that its light falls directly on the plastic bag.
Put a few drops of ink in the water.
The student did not observe any circulation of ink in the water as expected because the experiment had a flaw. Which of these statements best describes the flaw in the experiment? (2 points)
Not enough ink was added.
Not enough water was taken.
The dish was too small for the experiment.
The lamp and the ice bag were at the same place.
That answer would be, (B) Search Engines
Answer:
The page field is 8-bit wide, then the page size is 256 bytes.
Using the subdivision above, the first level page table points to 1024 2nd level page tables, each pointing to 256 3rd page tables, each containing 64 pages. The program's address space consists of 1024 pages, thus we need we need 16 third-level page tables. Therefore we need 16 entries in a 2nd level page table, and one entry in the first level page table. Therefore the size is: 1024 entries for the first table, 256 entries for the 2nd level page table, and 16 3rd level page table containing 64 entries each. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 2 (one second-level paget table) + 16 * 64 * 2 (16 third-level page tables) = 4608 bytes.
First, the stack, data and code segments are at addresses that require having 3 page tables entries active in the first level page table. For 64K, you need 256 pages, or 4 third-level page tables. For 600K, you need 2400 pages, or 38 third-level page tables and for 48K you need 192 pages or 3 third-level page tables. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 3 * 2 (3 second-level page tables) + 64 * (38+4+3)* 2 (38 third-level page tables for data segment, 4 for stack and 3 for code segment) = 9344 bytes.
Explanation:
16 E the answer
