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Lady_Fox [76]
3 years ago
7

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics
2 answers:
Ivenika [448]3 years ago
6 0
The trend line(BEST FIT LINE)
fiasKO [112]3 years ago
4 0

Answer:

Trend line (Best fit line).

Explanation:

In scatter plots the trend line gives the best approximation of the data. The approximation is of a linear equation. With this line it can be easy to estimate more values for a given x value. The graph here shows the distance covered in the corresponding time. The trend line here is a function of distance and time.

So, the name of the part of the graph labeled 7 is the Trend line (Best fit line).

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A liquid is flowing through a horizontal pipe whose radius is m. The pipe bends straight upward through a height of 10.6 m and j
zaharov [31]

Answer:

Volume flow rate = 1.81 * 10^{-2} meter cube per second

Explanation:

As we know that the

Pressure at the two ends would be the same along with volume of flow.

i.e

P_1 = P_2

and

A_1 V_1 = A_2 V_2

Re arranging the file, we get -

V_1 = \frac{A_2 V_2}{A_1}

The flow equation is

\frac{1}{2}\rho * V_1^2 = \frac{1}{2}\rho * V_2^2 + \rho * g * h\\

Substituting the value of V_1 in above equation, we get -

V_2 = \sqrt{\frac{2gh}{(\frac{A_2}{A_1})^2-1} }

Substituting the given values in above equation we get

V_2 = \sqrt{\frac{2*9.8*10.6}{(\frac{\pi 0.04^2}{\pi 0.02^2} )^2 -1} }\\ V_2 = 3.61 m

Volume flow rate

Q_2 = A_2 V_2\\= \pi r_2^2V_2^2\\= 3.14 * 0.04^2 * 3.61 \\= 1.81 * 10^{-2}

7 0
3 years ago
Need help ASAP ????????
zloy xaker [14]

Answer:

Question 1 is true, question 2 is b

8 0
3 years ago
Two point charges, 3.4 μC and -2.0 μC , are placed 5.0 cm apart on the x axis. Assume that the negative charge is at the origin,
Elza [17]

The electric field is zero at x = -16.45cm

Data;

  • q1 = 3.4 μC
  • q2 = -2.0 μC
  • distance = 5cm

<h3>The Electric Field at point 0</h3>

As the 3μC is larger than -2.0μC  and the charges are opposite sign. The electric field will be zero at the negative axis.

Let the point be at x.

For an electric field to be equal to zero;

k(\frac{q_1}{d_1})^2 + k(\frac{q_2}{d_2})^2 = 0\\\frac{3.4}{(5-x)^2} - \frac{2}{x^2} = 0\\

Let's solve for x using mathematical methods.

\frac{3.4x^2 - 2(5-x)^2}{(5-x)^2x^2}= 0\\ 3.4x^2 - 2(5-x^2) = 0\\3.4x^2 - 50 - 2x^2 + 20x = 0\\1.4x^2 +20x - 50 = 0

Solving the above quadratic equation;

x = -16.45cm

The electric field is zero at x = -16.45cm

Learn more on electric field at a point here;

brainly.com/question/1592046

brainly.com/question/14372859

8 0
3 years ago
What is the wavelength associated with 0.113kg ball traveling with velocity of 43 m/s?
lawyer [7]

Answer:

22

Explanation:

3 0
3 years ago
Who was Christa McAuliffe and what happened this year to make her dream come true?
Kryger [21]
On July 19th, 1985 Christa McAuliffe was selected as the first teacher to go to space by NASA. Her dream was to be the first teacher to go to space  with all her lessons. Her daughter keeps her dream alive today by setting up 40 schools called the McAuliffe Centre.
5 0
3 years ago
Read 2 more answers
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