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kakasveta [241]
4 years ago
13

If a freely falling object were equipped with a speedometer on a planet where the acceleration due to gravity is 20 m/s², then i

ts speed reading would increase each second by If a freely falling object were equipped with a speedometer on a planet where the acceleration due to gravity is 20 m/s², then its speed reading would increase each second by __________.a. 10 m/s. b. 30 m/s. c. 20 m/s. d. 40 m/s. e. depends on its initial speed
Physics
2 answers:
babymother [125]4 years ago
7 0

Answer:

20 m/s

Explanation:

The acceleration of an object determines the increase in velocity per second.

In this case the acceleration is 20m/s^2.

a=\frac{v}{t}=\frac{\frac{20m}{s}}{s}

That is, the increase is 20m/s each second.

I hope this is useful for you

Regards

DanielleElmas [232]4 years ago
7 0

Answer:

velocity will increase 20 m/sec each second

Explanation:

Given that the acceleration due gravity is g=20m/sec^2

We have to find the increase in the speed each second

We know that acceleration is nothing but rate of change of velocity as it changes  20m/sec^2 so the speed will also changes with 20 m/sec  

the object is falling freely so initial velocity u =0 m/sec

Acceleration due to gravity g= 20 m/s²

Time = 1 sec

From first law of motion

v=u+gt\\=0+20\times 1\\=20m/sec

the velocity will increase 20 m/sec each second

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The index of refraction for red light in water is 1.331 and that for blue light is 1.340. A ray of white light enters the water
Alex Ar [27]

Answer:

(a) 47.08°

(b) 47.50°

Explanation:

Angle of incidence  = 78.9°

<u>For blue light : </u>

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for blue light which is 1.340

n₁ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.340}

{sin\theta_2}=0.7323

Angle of refraction for blue light = sin⁻¹ 0.7323 = 47.08°.

<u>For red light : </u>

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for red light which is 1.331

n₁ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.331}

{sin\theta_2}=0.7373

Angle of refraction for red light = sin⁻¹ 0.7373 = 47.50°.

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Chemical energy, your welcome (:
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3 years ago
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makvit [3.9K]

Answer:

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Explanation:

E_peak = 14 V

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f = 1200rpm = (1200rp/m x 1m/60sec) = 20 revolutions per second

At peak performance, peak voltage is given by the equation;

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Let's make the magnetic field B the subject;

B = E_peak/(NAω)

Now we know that ω = 2πf

Thus, ω = 2π x 20 revs/s = 125.664 revs/s.

Let's convert it to the standard unit which is rad/s.

1 rev/s = 6.283 rad/s

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Area (A) = πr² = π x 0.05² = 0.007854 m²

Thus, plugging in the relevant values to get;

B = 14/[(250 x 0.007854 x 789.55)] = 0.009T

8 0
3 years ago
Differentiate between:<br>Transverse wave and Longitudin<br>Crest and Trough​
tester [92]

Answer:

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3 years ago
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