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kakasveta [241]

4 years ago

13

If a freely falling object were equipped with a speedometer on a planet where the acceleration due to gravity is 20 m/s², then i

ts speed reading would increase each second by If a freely falling object were equipped with a speedometer on a planet where the acceleration due to gravity is 20 m/s², then its speed reading would increase each second by __________.a. 10 m/s. b. 30 m/s. c. 20 m/s. d. 40 m/s. e. depends on its initial speed

2 answers:

babymother [125]4 years ago

7 0

Answer:

20 m/s

Explanation:

The acceleration of an object determines the increase in velocity per second.

In this case the acceleration is 20m/s^2.

$a=\frac{v}{t}=\frac{\frac{20m}{s}}{s}$

That is, the increase is 20m/s each second.

I hope this is useful for you

Regards

DanielleElmas [232]4 years ago

7 0

Answer:

velocity will increase 20 m/sec each second

Explanation:

Given that the acceleration due gravity is $g=20m/sec^2$

We have to find the increase in the speed each second

We know that acceleration is nothing but rate of change of velocity as it changes $20m/sec^2$ so the speed will also changes with 20 m/sec

the object is falling freely so initial velocity u =0 m/sec

Acceleration due to gravity g= 20 m/s²

Time = 1 sec

From first law of motion

$v=u+gt\\=0+20\times 1\\=20m/sec$

the velocity will increase 20 m/sec each second

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While entering a freeway, a car accelerates from rest at a rate of 2.40 m/s2 for 12.0 s. (a) Draw a sketch of the situation. (b)

ArbitrLikvidat [17]

Answer:

a) See attached picture, b) We know the initial velocity = 0, initial position=0, time=12.0s, acceleration= $2.40m/s^{2}$ , c) the car travels 172.8m in those 12 seconds, d) The car's final velocity is 28.8m/s

Explanation:

a) In order to draw a sketch of the situation, I must include the data I know, the data I would like to know and a drawing of the car including the direction of the movement and its acceleration, just like in the attached picture.

b) From the information given by the problem I know:

initial velocity =0

acceleration = $2.40m/s^{2}$

time = 12.0 s

initial position = 0

c)

unknown:

displacement.

in order to choose the appropriate equation, I must take the knowns and the unknown and look for a formula I can use to solve for the unknown. I know the initial velocity, initial position, time, acceleration and I want to find out the displacement. The formula that contains all this data is the following:

$x=x_{0}+V_{x0}t+\frac{1}{2}a_{x}t^{2}$

Once I got the equation I need to find the displacement, I can plug the known values in, like this:

$x=0+0(12s)+\frac{1}{2}(2.40\frac{m}{s^{2}} )(12s)^{2}$

after cancelling the pertinent units, I get that my answer will be given in meters. So I get:

$x=\frac{1}{2} (2.40\frac{m}{s^{2}} )(12s)^{2}$

which solves to:

$x=172.8m$

So the displacement of the car in 12 seconds is 172.8m, which makes sense taking into account that it will be accelerating for 12 seconds and each second its velocity will increase by 2.4m/s.

d) So, like the previous part of the problem, I know the initial position of the car, the time it travels, the initial velocity and its acceleration. Now I also know what its final position is, so we have more than enough information to find this answer out.

I need to find the final velocity, so I need to use an equation that will use some or all of the known data and the unknown. In order to solve this problem, I can use the following equation:

$a=\frac{V_{f}-V_{0} }{t}$

Next, since I need to find the final velocity, I can solve the equation just for that, I can start by multiplying both sides by t so I get:

$at=V_{f}-V_{0}$

and finally I can add $V_{0}$ to both sides so I get:

$V_{f}=at+V_{0}$

and now I can proceed and substitute the known values:

$V_{f}=at+V_{0}$

$V_{f}=(2.40\frac{m}{s^{2}}} (12s)+0$

which solves to:

$V_{f}=28.8m/s$

8 0

3 years ago

Read 2 more answers

HELP THIS IS URGENT! IT WOULD BE GREATLY APPRECIATED IF YOU ANSWER ALL BUT ONE IS FINE!

sukhopar [10]

Answer:

1 both increase

2. highest to lowest A C D B

3 the kinetic energy is higher in the larger vehicle as they have the same speed

Explanation:

6 0

3 years ago

The deflection of alpha particles in rutherford’s gold foil experiments resulted in what change to the atomic model? the additio

skelet666 [1.2K]

The answer is: The addition of a small dense nucleus at the center of the atom.

5 0

3 years ago

Read 2 more answers

Particles of m1 and m2 (m2>m1) are connected by a line in extensible string passing over a smooth fixed pulley. Initially, bo

Tresset [83]

Answer:

The velocity with which the mass will hit the floor is $v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.}$

Explanation:

If the tension in the string is $T$ , for $m_1$ we have

$T- m_1g =m_1a$ ,

and for the mass $m_2$

$T -m_2g = -m_2a$

From these equations we solve for $a$ and get:

$a =(\dfrac{m_2-m_1}{m_2+m_1}) g.$

The kinematic equation

$v_f^2 = v_0^2+2ax$

gives the final velocity $v_f$ of a particle, when its initial velocity was $v_0$ , and has traveled a distance $x$ while undergoing acceleration $a$ .

In our case

$v_0 = 0$ (the initial velocity of the particles is zero)

$a =(\dfrac{m_2-m_1}{m_2+m_1}) g.$

which gives us

$v_f^2 = 2ax$

$v_f^2 =2(\dfrac{m_2-m_1}{m_2+m_1}) g$

$\boxed{v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.} }$

which is the velocity with which the mass $m_2$ will hit the floor.

8 0

3 years ago

Does wavelength affect the energy of a wave?

Galina-37 [17]

Answer:

Not quite

Explanation:

The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength

What determines the strength of a wave?

Wave height is affected by wind speed, wind duration (or how long the wind blows), and fetch, which is the distance over water that the wind blows in a single direction. If wind speed is slow, only small waves result, regardless of wind duration or fetch.

So,

As Wavelength increases, The energy of the wave spreads and it decreases

4 0

2 years ago