No, the light from the overhead would show you only the coin outline.
Momentum of an object is defined as product of mass and velocity
so it is given as

here it is given that
mass = 0.15 kg
momentum = 6 kg m/s
so by plug in values in the above equation



so its speed will be 40 m/s
Answer:

Explanation:
Given that:
A circuit with a lagging 0.7 pf delivers 1500 watts and 2100VA
Here:
the initial power factor i.e cos θ₁ = 0.7 lag
θ₁ = cos⁻¹ (0.7)
θ₁ = 45.573°
Active power P = 1500 watts
Apparent power S = 2100 VA
What amount of vars must be added to bring the pf to 0.85
i.e the required power factor here is cos θ₂ = 0.85 lag
θ₂ = cos⁻¹ (0.85)
θ₂ = 31.788°
However; the initial reactive power
= P×tanθ₁
the initial reactive power
= 1500 × tan(45.573)
the initial reactive power
= 1500 × 1.0202
the initial reactive power
= 1530.3 vars
The amount of vars that must therefore be added to bring the pf to 0.85
can be calculated as:





Answer:
566.3 m
Explanation:
The distance travelled by the object can be found by using the SUVAT equation:

where
u is the initial velocity
t is the time
a is the acceleration
For the object in this problem:
u = 19 m/s
a = 2.5 m/s^2
Substituting t = 15 s, we find the distance travelled:
