Question

A thin coil has 16 rectangular turns of wire. When a current of 3 A runs through the coil, there is a total flux of 4 × 10-3 T·m2 enclosed by one turn of the coil (note that , and you can calculate the proportionality constant ). Determine the inductance in henries.

Answer 1

Answer:

The inductance is 0.021 H.

Explanation:

Given that,

Number of turns = 16

Current = 3 A

Total flux $\phi=4\times10^{-3}\ Tm^2$

We need to calculate the inductance

Using formula of total flux

$N\phi = Li$

$L=\dfrac{N\phi}{i}$

Where, i = current

N = number of turns

$\phi$ = flux

Put the value into the formula

$L=\dfrac{16\times4\times10^{-3}}{3}$

$L=0.021\ H$

Hence, The inductance is 0.021 H.