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4 years ago

Which explains earthquakes and volcanic eruptions?

Physics

2 answers:

Nina [5.8K]4 years ago

8 0

<h3><u>Answer;</u></h3>

Plate tectonics theory

<h3><u>Explanation;</u></h3>

According to the plate tectonics theory, the plates making the earth float on the partially molten mantle, moving away from the mid ocean ridges at varying speeds. <em><u>At a point where the plates pull apart, slide or collide, a tectonic activity will be manifested as earthquakes. </u></em>
<em><u>Earthquakes </u></em><em><u>take place when the plate boundaries get stuck together while the plates keep moving. </u></em><em><u>Volcanoes </u></em><em><u>on the other hand take place when plates crash into or pull away from each other and hot magma from below rises up to the surface in an eruption.</u></em>

Phoenix [80]4 years ago

5 0

I think the answer is plate tectonics theory because when the are moving, they sometimes hit each other and it makes earthquakes and volcanic eruptions

But i'm not sure

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The process of examining a change in one variable in a model while assuming that all the other variables remain constant is call

mixer [17]

Answer:

<em>Ceteris Paribus</em>

Explanation:

The process of examining a change in one variable in a model while assuming that all the other variables remain constant is called <em><u>Ceteris Paribus</u></em>.

<em>Ceteris Paribus</em> is a Latin phrase that means "all other things being equal" or "all other things held constant" in English. The phrase has found application in disciplines like Economics and Statistics. This phrase as being adopted as a process of examining a change in one variable in a model while assuming that all the other variables remain constant to ascertain the relationship between the variables or make deductions from an experimental study. An example of <em>Ceteris Paribus</em> application is the law of demand and supply in Economics. The law of demand states, <em>Ceteris Paribus</em>, the higher the price, the lower the quantity demanded and <em>vice versa. </em>Conversely, the law of supply states, <em>Ceteris Paribus</em>, the higher price, the higher the quantity supply and <em>vice versa</em>.

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3 years ago

What does a fire burn a hole right in the middle of the chair???

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4 years ago

A pan hangs from a 50 cm spring. When a 10 kg mass is placed in the pan, it stretches the spring 6 cm. What is a function rule l

MrRissso [65]

Answer:

Explanation:

A Spring stretches / compresses when force is applied on them and they are governed by the Hookes Law which states that the force required to stretch or compress a spring is directly proportional to the distance it is stretched.

$F = -kx$

F is the force applied and x is the elongation of the spring

k is the spring constant.

negative sign indicates the change in direction from equilibrium position.

In the given question, we dont have force but we know that the pan is hanging. We also know from the Newton's second law of motion that

$F=mg$

Inserting this into Hooke's Law

$mg=-kx$

computing it for x,

$-x=mg/k$

This is the model which will tell the length of the spring against change in the mass located in the pan.

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3 years ago

What is used to measure heat?

Tcecarenko [31]

Answer:

change in temperature

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3 years ago

Read 2 more answers

Two billiard balls of equal mass move at right angles and meet at the origin of an xy coordinate system. Initially ball A is mov

frez [133]

Answer:

Speed of ball A after collision is 3.7 m/s

Speed of ball B after collision is 2 m/s

Direction of ball A after collision is towards positive x axis

Total momentum after collision is m×4·21 kgm/s

Total kinetic energy after collision is m×8·85 J

Explanation:

<h3>If we consider two balls as a system as there is no external force initial momentum of the system must be equal to the final momentum of the system</h3>

Let the mass of each ball be m kg

v $_{1}$ be the velocity of ball A along positive x axis

v $_{2}$ be the velocity of ball A along positive y axis

u be the velocity of ball B along positive y axis

Conservation of momentum along x axis

m×3·7 = m× v $_{1}$

∴ v $_{1}$ = 3.7 m/s along positive x axis

Conservation of momentum along y axis

m×2 = m×u + m× v $_{2}$

2 = u + v $_{2}$ → equation 1

<h3>Assuming that there is no permanent deformation between the balls we can say that it is an elastic collision</h3><h3>And for an elastic collision, coefficient of restitution = 1</h3>

∴ relative velocity of approach = relative velocity of separation

-2 = v $_{2}$ - u → equation 2

By adding both equations 1 and 2 we get

v $_{2}$ = 0

∴ u = 2 m/s along positive y axis

Kinetic energy before collision and after collision remains constant because it is an elastic collision

Kinetic energy = (m×2² + m×3·7²)÷2

= 8·85×m J

Total momentum = m×√(2² + 3·7²)

= m× 4·21 kgm/s

3 0

4 years ago