A 2 mole sample of F2(g) reacts with excess NaOH(aq) according to the equation above. If the reaction is repeated with excess Na
1 answer:
Answer:
The amount of NaF produced is doubled.
(d) is correct option.
Explanation:
Given that,
A 2 mole sample of F₂ reacts with excess NaOH according to the equation.
The balance equation is
If the reaction is repeated with excess NaOH but with 1 mole of F₂
The balance equation is
Hence, The amount of NaF produced is doubled.
(d) is correct option.
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Answer:- 2.39 mL are required.
Solution:- It's a dilution problem and to solve this type of problems we use the dilution equation:
Where, and
are molarities of concentrated and diluted solutions and
and
are their respective volumes.
= 1.10M
= 5.00mM = 0.005M (since, mM stands for milli molar and M stands for molar. 1M = 1000mM)
= ?
= 525 mL
Let's plug in the given values in the formula:
So, 2.39 mL of 1.10M are needed to make 525 mL of 5.00mM solution.
There are 11 Carbon atoms in the compound.
<u>Solution:</u>
Carbon atom count is the ratio of the M peak to the M+1 peak.
Here M peak is 57.10% and M+1 peak is 6.83%. On applying the values in the formula we get,
Therefore, the number of Carbon atoms in the compound are 11.
Refer the image attached below for a better understanding of M peak and M+1 peak.
The heaviest ion that has the greatest m/z value is said to be the molecular ion peak in mass spectrum.
