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AnnyKZ [126]
3 years ago
9

A 2 mole sample of F2(g) reacts with excess NaOH(aq) according to the equation above. If the reaction is repeated with excess Na

OH(aq) but with 1 mole of F2(g), which of the following is correct?
Group of answer choices

The amount of OF2(g) produced is doubled.

The amount of OF2(g) produced is halved.

The amount of NaF(aq) produced remains the same.

The amount of NaF(aq) produced is doubled.
Chemistry
1 answer:
77julia77 [94]3 years ago
6 0

Answer:

The amount of NaF produced is doubled.

(d) is correct option.

Explanation:

Given that,

A 2 mole sample of F₂ reacts with excess NaOH according to the equation.

The balance equation is

2F_{2}+2NaOH\Rightarrow 2NaF +H_{2}O+OF_{2}

If the reaction is repeated with excess NaOH but with 1 mole of F₂

The balance equation is

F_{2}+2NaOH\Rightarrow 2NaF +2OH

Hence, The amount of NaF produced is doubled.

(d) is correct option.

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If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi
zlopas [31]

Answer:

T_{eq}=28.9\°C

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

Q_{Cd}+Q_{W}=0

Thus, we insert mass, specific heat and temperatures to obtain:

m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}

Now, we plug in to obtain:

T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

Best regards!

6 0
3 years ago
Help me pleaseee. ty if you dooo :))
Lina20 [59]

\huge \fcolorbox{black}{red}{♛answer♛}

Hydrogen Fluoride / HF

\huge\sf\underline{\underline{\red{❥︎ Thanks}}}

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Explanation:

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