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AnnyKZ [126]
3 years ago
9

A 2 mole sample of F2(g) reacts with excess NaOH(aq) according to the equation above. If the reaction is repeated with excess Na

OH(aq) but with 1 mole of F2(g), which of the following is correct?
Group of answer choices

The amount of OF2(g) produced is doubled.

The amount of OF2(g) produced is halved.

The amount of NaF(aq) produced remains the same.

The amount of NaF(aq) produced is doubled.
Chemistry
1 answer:
77julia77 [94]3 years ago
6 0

Answer:

The amount of NaF produced is doubled.

(d) is correct option.

Explanation:

Given that,

A 2 mole sample of F₂ reacts with excess NaOH according to the equation.

The balance equation is

2F_{2}+2NaOH\Rightarrow 2NaF +H_{2}O+OF_{2}

If the reaction is repeated with excess NaOH but with 1 mole of F₂

The balance equation is

F_{2}+2NaOH\Rightarrow 2NaF +2OH

Hence, The amount of NaF produced is doubled.

(d) is correct option.

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Which of the following is considered a drawback to using wind energy as a source of power?
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Answer:

Option (3)

Explanation:

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It is cost-effective and does not produce any kind of pollution and is completely a renewable energy, that it can generated again and again.

It does have certain drawbacks also, because <u>the area may sometime do not experience constant wind, due to which it cannot store energy. So frequent wind blowing areas are the best place to set up windmills</u>.

Thus, the correct answer is option (3)

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If some red cabbage indicator is added to a solution with an unknown ph and the color of the indicator turn to blue what can be
atroni [7]

Answer:

Neutral solution, pH of 7.

Explanation:

Red cabbage is a natural indicator which gives red color when an acid is added, green color when a base is added and <u>it gives blue color when a neutral solution is added. </u>

<u>Given that when some red cabbage indicator is added to a solution , it turns blue which means that the solution is a neutral solution. Neutral solution have a pH of 7.</u>

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Match the prefix used in naming binary molecule compounds with its corresponding number
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8 0
3 years ago
The standard entropy of liquid methanol at 298K is 126.8 J/K-mol and its heat capacity is 81.6 J/K-mol. Methanol boils at 337K w
USPshnik [31]

Explanation:

First, we will calculate the entropies as follow.

 \Delta S_{2} = C_{p_{2}} ln \frac{T_{2}}{T_{1}} J/K mol

As,   T_{1} = 298 K,         T_{2} = 373.8 K

Putting the given values into the above formula we get,

     \Delta S_{2} = C_{p_{2}} ln \frac{T_{2}}{T_{1}} J/K mol

                 = 81.6 ln (\frac{373.8}{298})

                 = 18.5 J/K mol

Now,

       \Delta S_{3} = \frac{\Delta H_{vap}}{T_{b.p}}

                  = \frac{35270 J}{373.8}

                  = 94.2 J/mol K

Also,

    \Delta S_{4} = C_{p_{4}} ln \frac{T_{2}}{T_{1}}

                = 43.89 \times ln (\frac{800}{373.8})

                = 33.4 J/K mol

Now, we will calculate the entropy of one mole of methanol vapor at 800 K as follows.

   \Delta S_{T} = \Delta S^{o}_{1} + \Delta S_{2} + \Delta S_{3} + \Delta S_{4}

                 = (126.8 + 18.5 + 94.2 + 33.4) J/K mol

                 = 272.9 J/K mol

Thus, we can conclude that the entropy of one mole of methanol vapor at 800 K is 272.9 J/K mol.

7 0
3 years ago
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