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AnnyKZ [126]
3 years ago
9

A 2 mole sample of F2(g) reacts with excess NaOH(aq) according to the equation above. If the reaction is repeated with excess Na

OH(aq) but with 1 mole of F2(g), which of the following is correct?
Group of answer choices

The amount of OF2(g) produced is doubled.

The amount of OF2(g) produced is halved.

The amount of NaF(aq) produced remains the same.

The amount of NaF(aq) produced is doubled.
Chemistry
1 answer:
77julia77 [94]3 years ago
6 0

Answer:

The amount of NaF produced is doubled.

(d) is correct option.

Explanation:

Given that,

A 2 mole sample of F₂ reacts with excess NaOH according to the equation.

The balance equation is

2F_{2}+2NaOH\Rightarrow 2NaF +H_{2}O+OF_{2}

If the reaction is repeated with excess NaOH but with 1 mole of F₂

The balance equation is

F_{2}+2NaOH\Rightarrow 2NaF +2OH

Hence, The amount of NaF produced is doubled.

(d) is correct option.

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A chemist prepares a solution of barium acetate by measuring out of barium acetate into a volumetric flask and filling the flask
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The given question is incomplete. The complete question is :

A chemist prepares a solution of barium acetate by measuring out 32 g of barium acetate into a 350 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's barium acetate solution. Round your answer to significant digits.

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Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

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Molarity=\frac{0.125\times 1000}{350ml}

Molarity=0.357M

Therefore, the concentration of solution is 0.375 mol/L

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