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noname [10]
3 years ago
8

When a negatively charged object moves in the opposite direction of an eletric field the potential energy of the object....

Chemistry
1 answer:
Natalija [7]3 years ago
4 0
I would say C Inscreases

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Lead (II) Acetate + Potassium Chromate
castortr0y [4]

Answer:

SOMEONE HURRY AND ANSWER THIS

Explanation:

8 0
2 years ago
Plzzz help me answer this question!!,!
omeli [17]
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7 0
3 years ago
Which species acts exclusively as spectator ions in this reaction
adelina 88 [10]

Answer:

K^+ and NO3^-

Explanation:

In a balanced ionic equation, we usually see the species that react to yield the main product in the reaction.

Consider the reaction;

Pb(NO3)2(aq) +2 KI(aq) -------> PbI2(s) + 2KNO3(aq)

The main product in this reaction is PbI2. Hence the balanced ionic equation is;

Pb^2+(aq) + 2I^-(aq) ------> PbI2(s)

Notice that K^+ and NO3^- did not participate in this reaction. All ions that are part of the molecular equation but do not participate in the ionic reaction equation are called spectator ions. Hence K^+ and NO3^- are spectator ions in this reaction as can be seen clearly above.

4 0
3 years ago
An object has a mass of 18 grams and its volume is 2cm3 Calculate density:​
Natalka [10]

Answer:

9g/cm^3 is the density

Explanation:

P = m/V

P = 18/2 = 9g/cm^3

(This is more of a physics question than chem btw)

6 0
2 years ago
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Problem Page Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 70. g of
shusha [124]

Answer:

The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}

Explanation:

1. Write down the balanced chemical reaction:

2C_{6}H_{14}_{(l)}+19O_{2}_{(g)}=12CO_{2}_{(g)}+14H_{2}O_{(g)}

2. Find the limiting reagent:

- First calculate the number of moles of hexane and oxygen with the mass given by the problem.

For the hexane:

70.0gC_{6}H_{14}*\frac{1molC_{6}H_{14}}{86.2gC_{6}H_{14}}=0.81molesC_{6}H_{14}

For the oxygen:

81.3gO_{2}*\frac{1molO_{2}}{32.0gO_{2}}=2.54molesO_{2}

- Then divide the number of moles between the stoichiometric coefficient:

For the hexane:

\frac{0.81}{2}=0.41

For the oxygen:

\frac{2.54}{19}=0.13

- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.

3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:

The calculations must be done with the limiting reagent, that is the oxygen.

81.3gO_{2}*\frac{1molO_{2}}{32gO_{2}}*\frac{12molesCO_{2}}{19molesO_{2}}*\frac{44.0gCO_{2}}{1molCO_{2}}=70.6gCO_{2}

7 0
3 years ago
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