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noname [10]
3 years ago
8

When a negatively charged object moves in the opposite direction of an eletric field the potential energy of the object....

Chemistry
1 answer:
Natalija [7]3 years ago
4 0
I would say C Inscreases

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Using the standard enthalpies of formation found in the textbook, determine the enthalpy change for the combustion of ethanol c2
ArbitrLikvidat [17]
Enthalpy of formation is calculated by subtracting the total enthalpy of formation of the reactants from those of the products. This is called the HESS' LAW.
ΔHrxn = ΔH(products) - ΔH(reactants)

Since the enthalpies are not listed in this item, from reliable sources, the obtained enthalpies of formation are written below.
ΔH(C2H5OH) = -276 kJ/mol
ΔH(O2) = 0 (because O2 is a pure substance)
ΔH(CO2) = -393.5 kJ/mol
ΔH(H2O) = -285.5 kJ/mol

Using the equation above,
ΔHrxn = (2)(-393.5 kJ/mol) + (3)(-285.5 kJ/mol) - (-276 kJ/mol)
ΔHrxn = -1367.5 kJ/mol

<em>Answer: -1367.5 kJ/mol</em>
6 0
3 years ago
Read 2 more answers
How do I write 0.03438 m in scientific notation using 3 digits?
Law Incorporation [45]
3.44x10^2
you move the decimal over to get a single digit number with change. The number of times you move the decimal is the number for the 10 power
4 0
2 years ago
Fluorite is..
denpristay [2]

Fluorite is harder than gypsum but softer than apatite. Thus, the correct option is B.

<h3>What is the hardness of any element?</h3>

The hardness of any element may be defined as the capability of a material to oppose the process of deformation and remains in actual shape precisely.  

According to the table of hardness scales by Mohs, the increasing order of given hardness of given elements is as follows:

Gypsum < Fluorite < Apatite.

Therefore, Fluorite is harder than gypsum but softer than apatite. Thus, the correct option is B.

To learn more about the Hardness of elements, refer to the link:

brainly.com/question/23721736

#SPJ1

5 0
1 year ago
Why is sugar considered an organic compound
Sliva [168]
Sugar is considered an organic compound,
Because it is made up a long chain of carbon atoms.
5 0
3 years ago
What is the wavelength of radiation emitted when an electron goes from the n = 7 to the n = 4 level of the Bohr hydrogen atom? G
Phantasy [73]

Answer:

the wavelength of radiation emitted  is \mathbf{\lambda= 2169.62 \ nm}

Explanation:

The energy of the Bohr's hydrogen atom can be expressed with the formula:

\mathtt{E_n =- \dfrac{13.6\ ev}{n^2}}

For n = 7:

\mathtt{E_7 =- \dfrac{13.6\ ev}{7^2}}

\mathtt{E_7 =-0.27755 \ eV}

For n = 4

\mathtt{E_4=- \dfrac{13.6\ ev}{4^2}}

\mathtt{E_4 =- 0.85\ eV}

The  electron goes from the n = 7 to the n = 4, then :

\mathtt{E_7-E_4 = (-0.27755 - (-0.85) ) \ eV}

\mathtt{= 0.57245\ eV}

Wavelength of the radiation emitted:

\mathtt{\lambda= \dfrac{hc}{0.57245 \ eV}}

where;

hc  = 1242 eV.nm

\mathtt{\lambda= \dfrac{1242 \ eV.nm }{0.57245 \ eV}}

\mathbf{\lambda= 2169.62 \ nm}

4 0
3 years ago
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