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borishaifa [10]
4 years ago
11

I need help!!! I need to have pictures for Absolute and Apparent Magnitude! Someone please help?!!!

Physics
1 answer:
valkas [14]4 years ago
7 0
Pictures you asked, I hope you like the pictures

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During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.22 s, how high does it rise? The accel
BigorU [14]

Answer:

47.4 m

Explanation:

When an object is thrown upward, it rises up, it reaches its maximum height, and then it goes down. The time at which it reaches its maximum height is half the total time of flight.

In this case, the time of flight is 6.22 s, so the time the ball takes to reach the maximum height is

t=\frac{6.22}{2}=3.11 s

Now we consider only the downward motion of the ball: it is a free fall motion, so we can find the vertical displacement by using the suvat equation

s=ut+\frac{1}{2}gt^2

where

s is the vertical displacement

u = 0 is the initial velocity

t = 3.11 s is the time

g=9.8 m/s^2 is the acceleration of gravity (taking downward as positive direction)

Solving the  formula, we find

s=\frac{1}{2}(9.8)(3.11)^2=47.4 m

7 0
4 years ago
What is it called when dolphins communicate underwater through sound waves?
frozen [14]

Answer: Echolocation

Explanation:

8 0
3 years ago
I need help immediately I appreciate it a lot :)
Rasek [7]
I honestly don’t know but I need some points , thank you
8 0
3 years ago
A block is released from the top of a frictionless incline plane as pictured above. If the total distance travelled by the block
kotegsom [21]

Complete Question

The diagram for this question is showed on the first uploaded image (reference homework solutions )

Answer:

The  velocity at the bottom is  v  = 11.76  \ m/ s

Explanation:

From the question we are told that

   The  total distance traveled is  d =  1.2  \ m

    The mass of the block is  m_b  =  0.3 \ kg

      The  height of the block from the ground is h =  0.60 m  

According the law of  energy  

   PE  =  KE

Where  PE  is the potential energy which is mathematically represented as

      PE  =  m * g  *  h

substituting values

     PE  =   3 *  9.8  *  0.60

      PE  =  17.64 \  J

So

   KE  is the kinetic energy at the bottom which is mathematically represented as

          KE  =  \frac{1}{2}  *  m v^2

So

      \frac{1}{2}  *  m* v ^2  =  PE

substituting values  

  =>    \frac{1}{2}  *  3 * v ^2  = 17.64

=>       v  = \sqrt{ \frac{ 17.64}{ 0.5 * 3 } }

=>    v  = 11.76  \ m/ s

4 0
4 years ago
Zona onde não incide luz visível devido à interposição de um objeto opaco.
m_a_m_a [10]

Answer:

can you please translate to english?

Explanation:

8 0
3 years ago
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